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Program and method for moving files between drives

I have 4 hard drives of backups of large files.  They are in no order.  I would like to arrange them alphabetically by file name amongst the drives. Only I don't have space to put them all in one location and then sort them out. Is there an automated way or script that would sort and move these files for me.

Thanks,
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mgjust
Asked:
mgjust
3 Solutions
 
ramromconsultant Commented:
Why? What advantage do you get from doing this? Beware that you could get trapped in a situation where a very large file might not fit at the end of drive 1, thus forcing it to drive 2 and leaving a big unused space on drive 1.

How much drive space is there and how much space do the files take up?

Would it not be better to maintain a directory of all files in alphabetic order rather than physically sorting them?

And is this a static backup, or are files added/deleted from time to time.
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mgjustAuthor Commented:
Its not static.
The advantage would be to find said files easily.

Is there an easy way to create a directory?
Thanks,
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efnCommented:
Assuming the number of files is not too huge, it would certainly be possible to write a script that would create an alphabetical index of the files.  I don't know of any off-the-shelf solution.
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peprCommented:
Here the example show only how to get the list of the files in separated directories. You can use shutil.copy2() for moving the files to the selected destination (http://docs.python.org/lib/module-shutil.html#l2h-2296). However, sorting is not necessary for the task... unless you want to display the files and let the user choose only some of them.
import os
 
def myCmp(a, b):
    '''Used for comparison of tuples based on first items.'''
    return cmp(a[0], b[0])
 
 
# The list of backup directories. Here the four drives are simulated in 
# four directories.
dirs = ['c:/tmp/backup1', 'c:/tmp/backup2', 'c:/tmp/backup3', 'c:/tmp/backup4']
 
# Build lst of tuples with bare name and full name. It assumes that all files
# in the directories are backup files. Otherwise, the list must be filtered 
# first.
lst = []
for d in dirs:
    lst.extend( (bare, os.path.join(d, bare)) for bare in os.listdir(d) )
 
# Now sort the list.
lst.sort(myCmp)
 
# Print the sorted bare names plus the full path to the file.
for bare, full in lst:
    print bare, full

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peprCommented:
The easy way of making the directory that does not exist is:

    os.mkdir(path)

or
 
    os.makedirs(path)         # makes also upper subdirectories if they do not exist

See http://docs.python.org/lib/os-file-dir.html#l2h-2688 
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