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PHP Validation / Form Post problem

Posted on 2007-11-15
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Last Modified: 2010-05-18
HI, I have a huge problem with checkout forms on my shopping cart.

As with most carts, the user must go through 3 or 4 steps to check and purchase products.

I have decided to do form validation on server side (i.e. using PHP), i think it's a little safer.

I have the following form ;

switch ($mode)
{
      case 'validate:
            // For register_global on PHP settings
            $first = mysql_real_escape_string($_POST['txtPaymentFirstName']);
                        
            //check mandatory fields
            if (empty($first)){ $first_error = "FIRST NAME IS MANDATORY"; }

            //Check for no errors, if no errors then move to next step
            if (empty($first_error)){
                 echo "<script language=\"JavaScript\"> window.location = '" . $_SERVER['PHP_SELF'] . "?step=2'</script>";      
                     exit;
            }      
                  
            break;
      }

<form action="<?php echo $_SERVER['PHP_SELF']; ?>?mode=validate&step=1" method="post" name="frmCheckout" id="frmCheckout">

      <input name="txtPaymentFirstName" type="text" class="box" id="txtPaymentFirstName" value="<?PHP echo $first ?>" size="30" maxlength="50" />
      <?PHP  if (empty($first_error)){} else{ echo $first_error; }  ?>


<input class="box" name="btnStep1" type="submit" id="btnStep1" value="Proceed &gt;&gt;" />
</form>

THE PROBLEM:
On the next step, I require the fields to be posted from the previous step. As you can see from the code, I exit the page if there are no errors and in turn, don't post the fields.

QUESTION:
How can I post the fields without reloading the whole page again? (there is going to be several fields, some of which will require trips to the database, so I would prefer not to load the whole page again).

Thanks
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Question by:jset_expert
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3 Comments
 
LVL 82

Expert Comment

by:hielo
ID: 20296389
You can save the fields and their values in hidden fields. That way if the user clicks on your form's "Edit" button (assuming you have one) or "Continue" and both are of type submit, you will still get the data:
<input type="hidden" name="firstName" value="John"/>
<input type="submit" name="step" value="Edit"/>
<input type="submit" name="step" value="Continue"/>

The other alternative is to save the data on Session variables.
0
 
LVL 21

Accepted Solution

by:
nizsmo earned 2000 total points
ID: 20296548
I suggest using session variables, it is quite hassle free and easy to pass variables.

To use session variables, put:
session_start(); at the start of every page you want to assign or access the variables.

Then to set the variables simply:

$_SESSION["your_variable_name"] = $your_variable;

and in another page you can do as you wish by retrieving the variable

session_start();
echo $_SESSION["your_variable_name"];

Hope this helps with your query.
0
 
LVL 1

Author Closing Comment

by:jset_expert
ID: 31409503
of course....can't believe i didn't think of this.
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