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Find the sum of 12 DIFFERENT random numbers

Posted on 2007-11-18
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Last Modified: 2010-04-30
Experts,

I need to assign a parameter 'b' as the sum of 12 different randomly generated numbers between 0 and 1. How do i do that - should i use a loop?
I need the code to do this automatically and assign the result to a variable 'b' as a value for use in other calcs.

Thanks everyone

Simon
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Question by:simondopickup
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10 Comments
 
LVL 55

Expert Comment

by:Jaime Olivares
ID: 20309115
Is this a homework?
some initial code to start helping you with?

0
 
LVL 25

Expert Comment

by:imitchie
ID: 20309138
I see you included this in Excel, are you after an Excel formula?
0
 
LVL 7

Expert Comment

by:tcicatelli
ID: 20309175
If you're in excel, place the formula =rand() into cells A1 through A12.  Then place the formula =sum(a1:a12) into cell a13.  This will work, but you will get a different answer everytime the spreadsheet recalculates.
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Accepted Solution

by:
imitchie earned 500 total points
ID: 20309192
if you're after Excel VBA, then here's something to get you started
it contains a template for a loop (to 5) and in each iteration, calls Rnd() once
the cells(2,i) shows you how it generates a different random value each time
instead of b = Rnd(), you can use b = b + Rnd() to add to b each time
Dim b As Double

b = 0

For i = 1 To 5

    b = Rnd()

    Cells(2, i) = b

Next

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Author Comment

by:simondopickup
ID: 20309307
i need to code this in vb. I dont want to write in cells  - i would rather populate an array and sum the elements..

currently by code is this which is so wrong!

b=rnd+rnd+rnd+rnd+rnd+rnd+rnd+rnd+rnd+rnd+rnd+rnd
0
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LVL 85

Expert Comment

by:Mike Tomlinson
ID: 20309467
Just like imitchie said...
Option Explicit
 

Private Sub Form_Load()

    Randomize

End Sub
 

Private Sub Command1_Click()

    Dim b As Double

    Dim value As Double

    Dim i As Integer

    

    For i = 1 To 12

        value = Rnd

        Debug.Print i, value

        b = b + value

    Next i

    Debug.Print "b = " & b

End Sub

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0
 
LVL 76

Expert Comment

by:GrahamSkan
ID: 20309494
Try it like this:

Sub Totalrnd()
    Dim r(11) As Double
    Dim i As Integer
    Dim j As Integer
    Dim d As Double
    Dim bFound As Boolean
    Dim b As Double
    Dim strMessage As String
    i = -1
    Randomize
    Do While i < 11
        d = Rnd()
        bFound = False
        For j = 0 To i
            If d = r(i) Then
                bFound = True
                Exit For
            End If
        Next j
        If Not bFound Then
            i = i + 1
            r(i) = d
            strMessage = strMessage & IIf(i > 0, " + ", "") & d
            b = b + d
        End If
    Loop
    strMessage = b & " = " & strMessage
    MsgBox strMessage
End Sub

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LVL 76

Expert Comment

by:GrahamSkan
ID: 20309516
I did check that each contributory element is different as you asked, but I bet, you couldn't produce two identical random numbers in such a sequence in a thousand years.
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LVL 25

Expert Comment

by:imitchie
ID: 20309578
i thought i'd leave something for your imagination but...
' old: b=rnd+rnd+rnd+rnd+rnd+rnd+rnd+rnd+rnd+rnd+rnd+rnd

' new: below, equivalent. drop the 4 lines where the 1 line above was

b = 0;

for i = 1 to 12

  b = b + rnd()

next i

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0
 

Author Closing Comment

by:simondopickup
ID: 31409832
Thanks!
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