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get the position of an array element

Posted on 2007-11-18
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Last Modified: 2012-05-05
below ic a copy of my array, I would like to know how to get the position of a particular element

eg  get the position of 1998
$yearArray = array("1994","1995","1996","1997","1998","1999","2000","2001","2002","2003","2004","2005","2006","2007","2008","2009");

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Question by:bdipasquale
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blue_hunter earned 250 total points
ID: 20310237
$yearArray = array("1994","1995","1996","1997","1998","1999","2000","2001","2002","2003","2004","2005","2006","2007","2008","2009");


$searchElement = "1998";
$position = array_search($searchElement, $yearArray); // $position = 4;


* position start at 0
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Assisted Solution

by:nizsmo
nizsmo earned 250 total points
ID: 20310460
alternatively you can define the key yourself like this:

$yearArray = array("year1" => "1994", "year2" => "1995", "year3" => "1996", "year4" => "1997", "year5" => "1998", "year6" => "1999", "year7" => "2000", "year8" => "2001", "year9" => "2002", "year10" => "2003", "year11" => "2004", "year12" => "2005", "year13" => "2006", "year14" => "2007", "year15" => "2008", "year16" => "2009");

so that you know exactly which element has which year, you can change the keys accordingly i did the above only as an example as an alternative solution.

To access year 2000:
echo $yearArray["year7"];

it all depends what you want to use the array for essentially, both methods have very different uses.
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