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# How do I determine week number in a month?

Posted on 2007-11-19
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Hello,

I have a batch job that I am writing that is scheduled to be run every Tuesday throughout the year.
I have a huge file that I am ftp'ing to another machine but I am dividing it up into 4 files.
The first Tuesday of the month will write all of the data to these four files and ftp the first file to
the other machine.The second, third, and fourth(last) Tuesday of the month will ftp the other files.

Now I need to determine what Tuesday in the month I am in.  So if it is the first Tuesday of the month, I need it to do some calculation and if it is the 2nd, 3rd, 4th Tuesday then my job will do something else.  I know there are circumstances where there are 5 Tuesdays in a month but I need to ignore that in my code.  Can someone provide me with the code or ideas to do this?

0
Question by:farekat
• 2

LVL 53

Expert Comment

ID: 20312335
Use struct tm :

You can easily detect whether a day is tuesday or not using the tm_wday field.
The day of the month can be found in tm_mday (note the first tuesday will have a tm_mday value <= 7, the second tuesday a value between 8 and 14, etc.).

So, something like :

``````#include <time.h>

time_t now;

struct tm *nowtm = 0;

time(&now);

nowtm = localtime(&now);

if (nowtm->tm_wday == 2) {  /* tueasday */

if (nowtm->tm_mday <= 7) {

/* first tuesday of the month */

}

else if (nowtm->tm_mday <= 14) {

/* second tuesday of the month */

}

else if (nowtm->tm_mday <= 21) {

/* third tuesday of the month */

}

else if (nowtm->tm_mday <= 28) {

/* fourth tuesday of the month */

}

}
``````
0

Author Comment

ID: 20313225
Would taking the actual date in the month (i.e. today = 19) and dividing it by 7+1 (using integers) give me the week number too?  Is there situations where that won't work?
0

LVL 53

Accepted Solution

Infinity08 earned 500 total points
ID: 20314004
if dom is the day of the month (1 ... 31) :

((dom - 1) / 7) + 1

would give you the week number (1, 2, etc.), assuming that / is integer division.
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