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TCHAR to int

Posted on 2007-11-19
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Last Modified: 2013-12-14
Ah hello.

This seems like it should have a simple solution, but I cannot find it.  I have a single TCHAR, obtained from CString::GetAt.  I need to convert it to an integer.

I cannot use _ttoi as that requires a TCHAR* not a TCHAR.

How can I convert a single character?

TIA
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Question by:mrwad99
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10 Comments
 
LVL 11

Expert Comment

by:DeepuAbrahamK
ID: 20312518
ttoi() -  did you try this?

Best regards,
DeepuAbrahamK
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LVL 55

Expert Comment

by:Jaime Olivares
ID: 20312523
just do a casting operation:

TCHAR a = somestring.GetAt(5);
int i = (int)a;
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LVL 11

Expert Comment

by:DeepuAbrahamK
ID: 20312538


int i = _ttoi((LPCTSTR)tchardata);

Try this way of casting as well
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LVL 19

Author Comment

by:mrwad99
ID: 20312563
Jaime:

      CString str ( _T("1") );
      TCHAR ch = str.GetAt ( 0 );
      int n34 = ( TCHAR ) ch;

This sets 'n34' to 49, not 1.

DeepuAbrahamK:

      CString str ( _T("1") );
      TCHAR ch = str.GetAt ( 0 );
      int n34 = _ttoi ( ( LPCTSTR )ch );
      

This crashes.

???
0
 
LVL 55

Accepted Solution

by:
Jaime Olivares earned 600 total points
ID: 20312573
not sure what you need
if you want to convert just 1 character to int, then:
int i = (int)a - 48;
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LVL 19

Author Comment

by:mrwad99
ID: 20312590
>> if you want to convert just 1 character to int, then:

Yes that is exactly what I need.  I get a TCHAR from CString::GetAt(), which I then need to convert to an int.  As I said above, I cannot use _ttoi as that requires a TCHAR* parameter, not a TCHAR.

>> int i = (int)a - 48;

That does the trick.  Can you explain why please, and can I 100% rely on this with UNICODE/non UNICODE apps ?
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LVL 55

Expert Comment

by:Jaime Olivares
ID: 20312654
the '0'  digit has always a value of 48, in both ASCII/ANSI and Unicode.
following numbers values are 49,50,etc.
So, this always will be true.

Just you have to handle what to do, when the caracter is not a digit, that is, with a value lower and 48 or greater than 57

0
 
LVL 19

Author Comment

by:mrwad99
ID: 20312983
OK, after consideration I understand that: if I output a character A via

int i = (int)a - 48;

I get 17.  Hence the need for the range test.  Interestingly, after looking on http://www.asciitable.com/, I see that 17 is not the decimal of 'A'.  Can you tell me why this please?  (Points up 50 now to 150 for this extra question)
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LVL 55

Expert Comment

by:Jaime Olivares
ID: 20313086
>>I see that 17 is not the decimal of 'A'.
I'm not sure on what you expect to have in this case.  Which is the decimal of A?
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LVL 19

Author Comment

by:mrwad99
ID: 20313113
Sorry, ignore me.  I was forgetting we had subtracted 48.  (The int equivalent of A is 65, but we subtracted 48 from that to give 17.)

Looking at the asciitable I see that characters 0 - 9 are in the range 48 - 57 (inclusive), which is why we do the range test.

All is clear now :)

Thanks a lot :)
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