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PrintWindow() screenshots and transparency

Posted on 2007-11-19
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Last Modified: 2008-02-01
I was wondering how I could take screenshots using PrintWindow() on Windows XP and get the transparency information, so I don't get an ugly black border around all my individual window screenshots. This seems to be possible from looking at other programs (e.g. TopDesk, http://www.otakusoftware.com/topdesk/). I played with calling GetLayeredWindowAttributes to find out transparency information, but it only succeeds for app that initially set the transparency information in the first place.
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Question by:mikejurka
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Author Comment

by:mikejurka
ID: 20317295
OK, figured it out! It seems like you can't get layered window information from PrintWindow. However, most windows "do transparency" via clipping window regions, which I didn't know about. I had to interop/import a few more functions relating to regions, and then I print the window to a bitmap and then draw it to another bitmap with the window region as a clipping frame. If someone can suggest a way to do this using only one bitmap, I'd really appreciate it!




            Rect rc;
            GetWindowRect(hwnd, out rc);
 
            if (rc.Width == 0 && rc.Height == 0)
            {
                return null;
            }
 
            System.Drawing.Bitmap bitmap = new System.Drawing.Bitmap((int)rc.Width, (int)rc.Height, System.Drawing.Imaging.PixelFormat.Format32bppArgb);
            System.Drawing.Graphics gfxBitmap = System.Drawing.Graphics.FromImage(bitmap);
 
            IntPtr hdcBitmap = gfxBitmap.GetHdc();
            PrintWindow(hwnd, hdcBitmap, 0);
            gfxBitmap.ReleaseHdc(hdcBitmap);
 
 
            IntPtr hRgn = CreateRectRgn(0, 0, 0, 0);
            GetWindowRgn(new IntPtr(hwnd), hRgn);
            System.Drawing.Region region = System.Drawing.Region.FromHrgn(hRgn);
            if (!region.IsEmpty(gfxBitmap))
            {
                System.Drawing.Bitmap bitmap2 = new System.Drawing.Bitmap((int)rc.Width, (int)rc.Height, System.Drawing.Imaging.PixelFormat.Format32bppArgb);
                System.Drawing.Graphics gfxBitmap2 = System.Drawing.Graphics.FromImage(bitmap2);
                gfxBitmap2.Clip = region;
                gfxBitmap2.DrawImage(bitmap, new System.Drawing.Point(0, 0));
                System.Drawing.Bitmap oldBitmap = bitmap;
                bitmap = bitmap2;
                oldBitmap.Dispose();
                gfxBitmap2.Dispose();
 
                //gfxBitmap.ExcludeClip(region);
                //gfxBitmap.FillRegion(new System.Drawing.SolidBrush(System.Drawing.Color.Red), region);
            }
 
            gfxBitmap.Dispose();

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Author Comment

by:mikejurka
ID: 20317344
OK, figured it out! Here's a way to do it using only one bitmap:

            Rect rc;
            GetWindowRect(hwnd, out rc);

            if (rc.Width == 0 && rc.Height == 0)
            {
                return null;
            }

            System.Drawing.Bitmap bitmap = new System.Drawing.Bitmap((int)rc.Width, (int)rc.Height, System.Drawing.Imaging.PixelFormat.Format32bppArgb);
            System.Drawing.Graphics gfxBitmap = System.Drawing.Graphics.FromImage(bitmap);

            IntPtr hdcBitmap = gfxBitmap.GetHdc();
            PrintWindow(hwnd, hdcBitmap, 0);
            gfxBitmap.ReleaseHdc(hdcBitmap);


            IntPtr hRgn = CreateRectRgn(0, 0, 0, 0);
            GetWindowRgn(new IntPtr(hwnd), hRgn);
            System.Drawing.Region region = System.Drawing.Region.FromHrgn(hRgn);

            if (!region.IsEmpty(gfxBitmap))
            {
                gfxBitmap.ExcludeClip(region);
                gfxBitmap.Clear(System.Drawing.Color.Transparent);
               
            }

            gfxBitmap.Dispose();
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