Solved

Select 3 random rows from dataset in ASP

Posted on 2007-11-20
5
1,080 Views
Last Modified: 2008-03-08
Hi,

I have the following asp script that reads from a ms sql database.
It currently returns the data for all rows.
Can somebody please modify this to return 3 different RANDOM rows instead of all data in the loop attached.

I've tried to modify and can't get it to work. Any help apreciated.
<html>
<!--#INCLUDE Virtual="/asp/user/dbHelpers.asp" -->
<%
 
sql = "SELECT listingStyle, EntryID, FullName, CompanySchoolGuild, City, State, Country FROM WebData WHERE Active = 1 AND EntryType = 'therapist'"
 
If listingType <> "" Then
	sql = sql & " AND EntryType =  '" & listingType & "'"
End If
 
if countryCode <> "" Then
	sql = sql & " AND country = '" & countryCode & "'"
End If
 
If state <> "" Then
	sql = sql & " AND state = '" & state & "'"
end if
 
sql = sql & " ORDER BY isnull(payedmembersince, '10/10/2100') ASC, CASE Country WHEN '' THEN 'ZZZZ' ELSE Country END ASC, CASE State WHEN '' THEN 'ZZZZ' ELSE State END ASC, CASE City WHEN '' THEN 'ZZZZ' ELSE City END ASC, FullName ASC, CompanySchoolGuild ASC"
 
' default is guild
title = "Hypnosis Guild &amp; Associations Listing"
 
fields = Array(Array("FullName", "Full Name"), Array("CompanySchoolGuild", "Company Name"), Array("City", "City"), Array("State", "State"), Array("Country", "Country"))
 
If listingType = "therapist" Then
	title = "Hypnotist &amp; Hypnotherapist Listing in the "
	If countryCode = "" Then
		title = title & "World"
	Else
		title = title & "United States"
	End If
ElseIf listingType = "school" Then
	title = "Hypnosis Schools &amp; Training Listing"
ElseIf listingType = "stage" Then
	title = "Stage Hypnotists Listing"
End If
 
Conn.Open(Application("HypnosisDB_ConnectionString"))
ObjRS.Open sql, conn, adOpenStatic, adLockReadOnly, adCmdText
 
Dim rows
hasResults = false
If ObjRS.EOF Then
	Redim rows(0,0)
Else
	rows = ObjRS.getRows()
	hasResults = true
End If
ObjRs.close()
 
%>
 
								<%
									for i=0 To ubound(fields)
										%>
											
										<%	
									next
								%>
						<BR>
						
							<%
								If hasResults Then
									for i=0 To ubound(rows, 2)
									%>
																				
											<a href="detail.asp?EntryID=<%= rows(1, i) %>"><font face="Verdana, Arial, Helvetica" size="2"><%= rows(2, i) %>&nbsp;</font></a>
																																					 
										<BR>
										
										<%
									Next
								End If
							%>

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Question by:superlative
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5 Comments
 
LVL 31

Expert Comment

by:James Murrell
ID: 20319168
If you just want a random row you can use the Random number function to generate the questionID value and then specify the value in your SELECT statement criteria:

"SELECT * FROM Questions WHERE questionID = " + RandomNumber();

 

You just need to determine the maximum questionID value (using the SQL MAX keyword) so that you can pass it to the RandomNumber function.

0
 
LVL 33

Accepted Solution

by:
raterus earned 500 total points
ID: 20319180
Replace these two lines with this,

sql = "SELECT top 3 listingStyle, EntryID, FullName, CompanySchoolGuild, City, State, Country FROM WebData WHERE Active = 1 AND EntryType = 'therapist'"


sql = sql & " ORDER BY newid(), isnull(payedmembersince, '10/10/2100') ASC, CASE Country WHEN '' THEN 'ZZZZ' ELSE Country END ASC, CASE State WHEN '' THEN 'ZZZZ' ELSE State END ASC, CASE City WHEN '' THEN 'ZZZZ' ELSE City END ASC, FullName ASC, CompanySchoolGuild ASC"
 
0
 

Author Comment

by:superlative
ID: 20319197
hi raterus, what two lines am i replaceing? am i using both of your sql lines?
0
 

Author Comment

by:superlative
ID: 20319206
hi raterus,

this line here

sql = "SELECT top 3 listingStyle, EntryID, FullName, CompanySchoolGuild, City, State, Country FROM WebData WHERE Active = 1 AND EntryType = 'therapist'"

works great.

now how do i get the top 3 results that show up to just randomize each time so its 3 different random results?
0
 
LVL 33

Expert Comment

by:raterus
ID: 20319528
The " ORDER BY newid() ", I posted in the second sql query is going to take care of this for you.
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