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How to create random number using oracle ?

Posted on 2007-11-22
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Last Modified: 2013-12-18
I want to create a random number between 1 to n and return any number within the range using sql. Our database is oracle 10g.
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Question by:KG1973
6 Comments
 
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Expert Comment

by:Naveen Kumar
ID: 20333280
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sujith80 earned 100 total points
ID: 20333283
Use the dbms_random package.

E.g.
SQL> select round(dbms_random.value(1, 100)) from dual;

ROUND(DBMS_RANDOM.VALUE(1,100))
-------------------------------
                             68

SQL> select round(dbms_random.value(1, 100)) from dual;

ROUND(DBMS_RANDOM.VALUE(1,100))
-------------------------------
                             31
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LVL 28

Expert Comment

by:Naveen Kumar
ID: 20333290
with the below code, i am able to generate 10 random numbers between 1 and 10

SET SERVEROUTPUT ON SIZE 1000000
DECLARE
  l_seed  BINARY_INTEGER;
BEGIN
  l_seed := TO_NUMBER(TO_CHAR(SYSDATE,'YYYYDDMMSS'));
  DBMS_RANDOM.initialize (val => l_seed);
  FOR cur_rec IN 1 ..10 LOOP
    DBMS_OUTPUT.put_line('value(low => 1, high => 10): ' || round(to_number(TO_CHAR(DBMS_RANDOM.value(low => 1, high => 10)))));
  END LOOP;
  DBMS_RANDOM.terminate;
END;
/

Thanks
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Assisted Solution

by:awking00
awking00 earned 25 total points
ID: 20340423
You can create a function -
create or replace function rand(n_in in number)
return number is
ret_n  number;
begin
ret_n := round(dbms_random.value(1,n_in));
return ret_n;
end;
/
Then input value for n
For example,
SQL> select rand(80) from dual;
  RAND(80)
----------
        60
SQL> /
  RAND(80)
----------
        36
,etc.
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Author Closing Comment

by:KG1973
ID: 31410527
Perfect solution.
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LVL 1

Author Comment

by:KG1973
ID: 20347505
You just solved my problem. Thank you very much.
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