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String.Replace() replce ' with \' not working

Posted on 2007-11-22
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Last Modified: 2013-12-16
Any ideas why strAddress.Replace("'","\'") doesn't work, it works with double backslash or any other text string but i just need to replace the quote with a backslash and quote

thanks
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Question by:stevejebson
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Expert Comment

by:Jens Fiederer
ID: 20336087
You have to backslash the backslash

strAddress.Replace("\"", "\\\"")

is proper.
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Expert Comment

by:Jaime Olivares
ID: 20336098
this will work too:
strAddress.Replace(@"'",@"\")
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Expert Comment

by:Jaime Olivares
ID: 20336107
also will work:
strAddress.Replace((char)39, (char)92);
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Author Comment

by:stevejebson
ID: 20336199
ok, maybe i'm doing something real stupid here 'cos none of these worked....

strAddress contains "St Jame's Place"

strAddress.Replace("\"", "\\\"")  gives me  "St Jame\\\'s Place"

strAddress.Replace(@"'",@"\")  gives me "St Jame\\'s Place"

and i can't get the syntax right with the (char)39,string.concat((char)92,(char)39)

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Expert Comment

by:Jens Fiederer
ID: 20336205
OK, it's hard to see these quotes on the screen - I thought you were trying to convert a DOUBLE QUOTE, not a single quote.


Try  

strAddress.Replace("'", "\\'")
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Expert Comment

by:Mike Tomlinson
ID: 20336206
Are you using the RETURN value from your call to Replace()?...

    strAddress = strAddress.Replace("x", "y");
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Expert Comment

by:Mike Tomlinson
ID: 20336208
*Just calling Replace on the string doesn't actually change the string!
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Expert Comment

by:Jens Fiederer
ID: 20336213
Since he is getting DIFFERENT values than the starting values, he must be using return values.
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Expert Comment

by:Jaime Olivares
ID: 20336231
Maybe you are looking the value of the string in the debugger windows. This could be confusing. Try to do this:

System.Windows.Forms.MessageBox.Show(strAddress);

to watch the string in a Window.
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Author Comment

by:stevejebson
ID: 20336282
that's it Jaime, why would the debugging window  lie ??
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Accepted Solution

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Jaime Olivares earned 500 total points
ID: 20336289
it doesn't lie, just is showing you the string in "C-language" style notation.
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Author Closing Comment

by:stevejebson
ID: 31410601
thanks very much, i coul have been on this for days ;-)
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