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bubble sort program sorting numbers in ascending order using java

Posted on 2007-11-27
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Last Modified: 2013-11-23
How to solve a problem where the program must arrange integers input by the user in ascending order. The user is prompted to input an amount of integers to be sorted & then the actual numbers. This program is a bubble sort problem
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Question by:s4suxs
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16 Comments
 
LVL 26

Accepted Solution

by:
ksivananth earned 1000 total points
ID: 20356409
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LVL 86

Assisted Solution

by:CEHJ
CEHJ earned 1000 total points
ID: 20356410
Study the following for your assignment before Java implementation:

http://en.wikipedia.org/wiki/Bubble_sort
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LVL 86

Expert Comment

by:CEHJ
ID: 20356432
>>here u go

Why not just supply ALL the code? ;-)


You'll need to read standard input http://www.exampledepot.com/egs/java.io/ReadFromStdIn.html
0
 
LVL 92

Expert Comment

by:objects
ID: 20356446
you caqn adapt the following to read user input into a file

http://www.objects.com.au/java/qa/908090699.html

just replace the file stream with stdin
and change the test condition for example to look for an empty line

the follwoing can be used to convert string to an int

http://www.objects.com.au/java/qa/590040453.html

let me know if u have any questions :)
0
 

Author Comment

by:s4suxs
ID: 20356798
this is what i got so far, but after i enter how many numbers i want to enter, it just enters all 0's.  for example, if i say that i want to input 5 numbers, it will automatically input 5 zeros and put them in order as the output, how do i fix it?
class SortArray
{
public static void main(String args[])
{
 Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int arr1[] = new int[n];
 
 int entry[] = new int[x];
        BufferedReader dataIn = new BufferedReader(new InputStreamReader(System.in));
 
          for(int i = 0; i < entry.length; i++)
          {
               strEntry = dataIn.readLine();
               entry[i] = Integer.parseInt(strEntry);
               System.out.println();
          }
 
 
for (int i=0;i<arr1.length;i++)
System.out.println(arr1[i]);
for(int i=0;i<(arr1.length-1);i++)
{
for (int j=i+1;j<arr1.length;j++)
{
if(arr1[i]>arr1[j])
{
int x,y;
x=arr1[i];
y=arr1[j];
arr1[i] = y;
arr1[j] = x;
}
}
}
 
System.out.println("Array after sorting in ascending order");
System.out.println();
for (int i=0;i<arr1.length;i++)
System.out.println(arr1[i]);
 
}
}

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0
 
LVL 26

Expert Comment

by:ksivananth
ID: 20356816
>>          for(int i = 0; i < entry.length; i++)
          {
               strEntry = dataIn.readLine();
               entry[i] = Integer.parseInt(strEntry);
               System.out.println();
          }
>>

change to

          for(int i = 0; i < arr1.length; i++)
          {
               strEntry = dataIn.readLine();
               arr1[i] = Integer.parseInt(strEntry);
               System.out.println();
          }
0
 
LVL 26

Expert Comment

by:ksivananth
ID: 20356825
and you don't need entry array at all unless you want to have the user entry for some purpose!
0
 
LVL 26

Expert Comment

by:ksivananth
ID: 20356829
even if you want to have, you have to make a copy...
0
 

Author Comment

by:s4suxs
ID: 20361481
this is what i have so far, but i still cant figure out how to get the user to input their own numbers, who can help?
import java.util.Scanner;
import java.io.*;
 
class sam
{
public static void main(String args[])
{
 
         Scanner in = new Scanner(System.in);
         int n = in.nextInt();
         int arr1[] = new int[n];
 
        int entry[] = new int[n];
        BufferedReader dataIn = new BufferedReader(new InputStreamReader(System.in));
 
 
 
        for (int i=0;i<arr1.length;i++)
        System.out.println(arr1[i]);
 
                for(int i=0;i<(arr1.length-1);i++)
        {
                        for (int j=i+1;j<arr1.length;j++)
                {
                        if(arr1[i]>arr1[j])
                        {
                        int x,y;
                        x=arr1[i];
                        y=arr1[j];
                        arr1[i] = y;
                        arr1[j] = x;
                        }
                }
        }
 
                System.out.println("Array after sorting in ascending order");
                System.out.println();
                for (int i=0;i<arr1.length;i++) System.out.println(arr1[i]);
 
}
}

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0
 
LVL 92

Expert Comment

by:objects
ID: 20361543
use something like:

for (int i=0; i<n; i++)
{
   arr1[i] = Integer.parseInt(dataIn.readLine());
}
0
 
LVL 86

Expert Comment

by:CEHJ
ID: 20362007
You don't need a Scanner *and* a BufferedReader. You can get the numbers in a separate method:

    static int[] getNumbers() {
        Scanner s = new Scanner(System.in);
        int i = 0;
        int[] numbers = new int[256];
        System.out.print("Enter number (q to quit): ");
        while (s.hasNextInt()) {
            System.out.print("Enter number (q to quit): ");
            numbers[i++] = s.nextInt();
        }
        int[] truncated = new int[i];
        System.arraycopy(numbers, 0, truncated, 0, i);
        return truncated;
    }

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0
 

Expert Comment

by:blurterboy
ID: 37673764
How do I change this program so that it sorts numbers that the user inputs from the command line instead of the numbers that I have specified? Here is what I have.


public class BubbleSort{
 public static void main(String[] args)
 {
   
   for (String str: args) {
     System.out.println(str);
   }
 
   int i;
   int array[] = {5, 10, 297, 3, 18, 4, 5};
   
   for(i = 0; i < array.length; i++)
     System.out.print( array[i]+"  ");
   System.out.println();
   bubbleSort(array, array.length);
   
   for(i = 0; i < array.length; i++)
     System.out.print(array[i]+"  ");
   System.out.println();
  }
 
 public static void bubbleSort( int a[], int n ){
 int i, j,t=0;
 for(i = 0; i < n; i++){
 
   for(j = 1; j < (n-i); j++){
     if(a[j-1] > a[j]){
       t = a[j-1];
       a[j-1]=a[j];
       a[j]=t;
 }
 }
 }
 }
}

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