Solved

Access:Average Year to Date in Query

Posted on 2007-11-27
4
1,178 Views
Last Modified: 2010-04-21
I have a table(Name: "Deliveries", Columns: "Ontime", "Late", "Month", "Year"
When a delivery is ontime it is labled 1, when it is late it is labled 0

The SQL below lists each month, number of deliveries ontime, number deliveries late, as well as the number of average deliveries on-time for each month. How do I add Average year to date to the mix?

Current CODE:
SELECT Deliveries.MonthandYear, Sum(Deliveries.ontime) AS [Delivery On-Time], Format(Avg([ontime]*100),"Fixed") AS [Percent Delivery On-Time for month], Sum(Deliveries.late) AS [Late Deliveries]
FROM Deliveries
GROUP BY Deliveries.MonthandYear, Deliveries.year_thru, Deliveries.month_thru
ORDER BY Deliveries.year_thru, Deliveries.month_thru;

Current Table Looks Like:

Field:              Month                Delivery On-Time   Delivery Late   Percent Delivery On-Time for month
Row1         August 2006                     53                      20                                   72.60            
Row2         September 2006              30                       10                                   75.00
Row3         October 2006                   60                       5                                     92.31
Row4         November 2006               20                       3                                     86.96
Row5         December 2006               15                       1                                     93.75

I NEED THE TABLE TO LOOK LIKE THIS:

Field:              Month    Delivery On-Time   Delivery Late   Percent Delivery On-Time for month      YearToDate
Row1       August 2006           53                      20                                  72.60                                     72.60      
Row2       September 2006     30                       10                                  75.00                                    73.45
Row3         October 2006        60                       5                                    92.31                                   80.34
Row4         November 2006    20                       3                                     86.96                                   81.09
Row5         December 2006    15                       1                                     93.75

0
Comment
Question by:ouestque
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
  • 2
4 Comments
 
LVL 26

Expert Comment

by:jerryb30
ID: 20361557
Not sure how you got your sql to work.  Looks like something from another query.
But, try this.
Did not format the percents as you would like them, but
SELECT a.monthandyear, Sum(a.ontime) AS [Delivery On-Time], Format([ontime]/([ontime]+[late])*100,"Fixed") AS [Percent Delivery On-Time for month], Sum(a.late) AS [Late Deliveries], DSum("ontime","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#")/(DSum("ontime","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#")+DSum("late","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#")) AS Year_To_Date_On_Time
FROM Deliveries AS a
GROUP BY a.monthandyear, Format([ontime]/([ontime]+[late])*100,"Fixed"), DSum("ontime","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#")/(DSum("ontime","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#")+DSum("late","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#"));
0
 
LVL 26

Accepted Solution

by:
jerryb30 earned 500 total points
ID: 20361568
OK, fixed formatting.
I had Monthandyear as a text field, hence the datevalue.

SELECT a.monthandyear, Sum(a.ontime) AS [Delivery On-Time], Format([ontime]/([ontime]+[late])*100,"Fixed") AS [Percent Delivery On-Time for month], Sum(a.late) AS [Late Deliveries], Format(DSum("ontime","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#")/(DSum("ontime","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#")+DSum("late","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#"))*100,"Fixed") AS Year_To_Date_On_Time
FROM Deliveries AS a
GROUP BY a.monthandyear, Format([ontime]/([ontime]+[late])*100,"Fixed"), Format(DSum("ontime","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#")/(DSum("ontime","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#")+DSum("late","deliveries","datevalue(monthandyear) <= #" & [a].[monthandyear] & "#"))*100,"Fixed"), DateValue([monthandyear])
ORDER BY DateValue([monthandyear]);
0
 

Author Comment

by:ouestque
ID: 20404956
Awesome Jerry thanks!!!
0
 

Author Closing Comment

by:ouestque
ID: 31411295
Increadible. Jerry had just the solution I needed. Thanks again.!
0

Featured Post

Creating Instructional Tutorials  

For Any Use & On Any Platform

Contextual Guidance at the moment of need helps your employees/users adopt software o& achieve even the most complex tasks instantly. Boost knowledge retention, software adoption & employee engagement with easy solution.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Phishing attempts can come in all forms, shapes and sizes. No matter how familiar you think you are with them, always remember to take extra precaution when opening an email with attachments or links.
Did you know that more than 4 billion data records have been recorded as lost or stolen since 2013? It was a staggering number brought to our attention during last week’s ManageEngine webinar, where attendees received a comprehensive look at the ma…
In Microsoft Access, learn how to use Dlookup and other domain aggregate functions and one method of specifying a string value within a string. Specify the first argument, which is the expression to be returned: Specify the second argument, which …
With Microsoft Access, learn how to specify relationships between tables and set various options on the relationship. Add the tables: Create the relationship: Decide if you’re going to set referential integrity: Decide if you want cascade upda…

696 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question