Solved

keep numbers after sign

Posted on 2007-11-27
1
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Last Modified: 2010-04-01
hello there,
I have this chars in here but instead of keeping the numbers I would like to keep the letters
the c++ source code is working fine I just would like to change it..

32423=wresdf
54456=uiohjk
567567567=cvbfgyhj
657567=sdfyui
6776=qwukij
#include <iostream>

#include <fstream>

#include <string>

using namespace std;
 

int main (int argc, char** argv)  {
 

    if (argc != 3) {
 

        cout << "Usage: program  <infile> <outfile>" << endl;
 

        return 0;

    }
 

    ifstream is;

    ofstream os;
 

    is.open(argv[1]);
 

    if (!is.is_open()) {
 

        cout << "Cannot open " << argv[1];
 

        return -1;

    }
 

    os.open(argv[2]);
 

    if (!os.is_open()) {
 

        cout << "Cannot open " << argv[2];
 

        return -1;

    }
 

    while(!is.eof()) {
 

        string str;
 

        getline(is,str);
 

        int pos = str.find('=');
 

        if (-1 != pos) str.erase(pos,str.length() - pos);
 

        os << str << endl; // line feed was missing

    }
 

    return 0;

}

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Question by:Woodie2986
1 Comment
 
LVL 7

Accepted Solution

by:
UrosVidojevic earned 125 total points
ID: 20362428
if (-1 != pos) str.erase(pos,str.length() - pos);

->

if (-1 != pos) str.erase(0, pos+1);
0

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