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XSL Session variable check syntax

Posted on 2007-11-27
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Last Modified: 2013-11-18
I have an xsl file that is being used on a web page to display a table that contains menu links. The menu tems are like -
Help    Subscribe   Return

On certain logins which are stored in a session variable - Session["LoginCheck"] I don't want to show the "return" menu item.
Is there certain syntax to do this or go about this?
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Question by:jandhb
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11 Comments
 
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Expert Comment

by:Geert Bormans
ID: 20363654
yes, you can set a parameter on the highest level in your stylesheet
<xsl:param name="loginCheck"/>

use that parameter in a test as $loginCheck

and pass the value of the ession variable to the stylesheet
I can show you how, if you show how you call the XSLT
Make sure you use a template processor instead of a simple transform
in order to be able to pass parameters

cheers


Geert
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Author Comment

by:jandhb
ID: 20365333
Geert,

When you say "use that parameter in a test as $loginCheck" can you show me how that would be done? In this particular case I just need to check if the value of that is > 1.

How would I pass the value of the session variable to the stylesheet? Right now I'm calling the XSLT with - <asp:Xml Runat="server" ID="xmlMenu" TransformSource="../navigation/menu.xslt" />
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Expert Comment

by:Geert Bormans
ID: 20365774
<xsl:choose>
  <xsl:when test="$loginCheck = 1">
    output the column here
  </xsl:when>
  <xsl:otherwise>
    don't output the column
  </xsl:otherwise>
</xsl:choose>

you can leave the "otherwise" clause out if you don't need it
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LVL 1

Author Comment

by:jandhb
ID: 20365787
ok, i follow that, but i thought you said i had to pass the session variable to the xslt page first?
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Expert Comment

by:Geert Bormans
ID: 20365809
yes, that is a bit trickier when you use an XML control
Here is an article that shows you how to do that

http://www.braintrove.com/article/13

cheers

Geert
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Author Comment

by:jandhb
ID: 20366205
I took a look at the article and have some quesions.

1. In the XSLT he is using xls:when should I use - <xsl:if test="$loginCheck > 1">

2. In my aspx this is not a query string. It is a session variable. So should I only do this without the request.querystring part?...

Args.AddParam("loginCheck ", "", loginCheck );
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Accepted Solution

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Geert Bormans earned 100 total points
ID: 20366270
1. xsl:when is a statement inide an xsl:choose
xsl:if is equivalent to a single xsl:when without an xsl:otherwise
the adventage of xsl:if is that you don't need the xsl:choose
<xsl:choose><xsl:when test="sometest">blabla</xsl:when></xsl:choose>
and
<xsl:if test="sometest">blabla</xsl:if>
are equivalent

note that in the XSLT you best replace > with &gt;
<xsl:if test="$loginCheck &gt; 1">

2. just make sure that the value for $loginCheck gets put in the loginCheck variable in the ASP
it doesn't really matter whether it comes originally from a session variable or a request string
This line is where you pass the variable to the parameter
Args.AddParam("loginCheck", "", loginCheck );
note that I removed a space in the first argument to the method

cheers

Geert
0
 
LVL 1

Author Comment

by:jandhb
ID: 20366351
I have this in my page load now...

XsltArgumentList Args = new XsltArgumentList();
 
    Args.AddParam("loginCheck", "", loginCheck );
 
    xmlMenu.TransformArgumentList = Args;

look right?
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Expert Comment

by:Geert Bormans
ID: 20366361
looks right
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Expert Comment

by:Computer101
ID: 21146866
Forced accept.

Computer101
EE Admin
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