XSL Session variable check syntax

yes, you can set a parameter on the highest level in your stylesheet
<xsl:param name="loginCheck"/>

use that parameter in a test as $loginCheck

and pass the value of the ession variable to the stylesheet
I can show you how, if you show how you call the XSLT
Make sure you use a template processor instead of a simple transform
in order to be able to pass parameters

cheers


Geert

Geert,

When you say "use that parameter in a test as $loginCheck" can you show me how that would be done? In this particular case I just need to check if the value of that is > 1.

How would I pass the value of the session variable to the stylesheet? Right now I'm calling the XSLT with - <asp:Xml Runat="server" ID="xmlMenu" TransformSource="../navigation/menu.xslt" />

<xsl:choose>
  <xsl:when test="$loginCheck = 1">
    output the column here
  </xsl:when>
  <xsl:otherwise>
    don't output the column
  </xsl:otherwise>
</xsl:choose>

you can leave the "otherwise" clause out if you don't need it

ok, i follow that, but i thought you said i had to pass the session variable to the xslt page first?

yes, that is a bit trickier when you use an XML control
Here is an article that shows you how to do that

http://www.braintrove.com/article/13

cheers

Geert

I took a look at the article and have some quesions.

1. In the XSLT he is using xls:when should I use - <xsl:if test="$loginCheck > 1">

2. In my aspx this is not a query string. It is a session variable. So should I only do this without the request.querystring part?...

Args.AddParam("loginCheck ", "", loginCheck );

I have this in my page load now...

XsltArgumentList Args = new XsltArgumentList();
 
    Args.AddParam("loginCheck", "", loginCheck );
 
    xmlMenu.TransformArgumentList = Args;

look right?

looks right

Forced accept.

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