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Outputting a char as an unsigned int

Posted on 2007-11-28
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Last Modified: 2008-02-01
Hi,

I'm attempting to output every possible char as an unsigned int (see code snippet). But this gives the following:

0
...
126
127
4294967168
4294967169
...
4294967295


But what I'm wanting is:
0
...
126
127
128
129
...
255


Thanks,
Uni
char mut=0;
cout<<(unsigned int)mut<<endl;
for(unsigned int i=0;i<256;i++){
	mut++
	cout<<(unsigned int)mut<<endl;
}

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Question by:Unimatrix_001
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4 Comments
 
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UrosVidojevic earned 500 total points
ID: 20370652
You must use unsigned char.
char type can contain negative values, which causes problems in your case, when you are converting char to unsigned int.

unsigned char mut=0;
for(unsigned int i=0;i<256;i++){
        cout<<(unsigned int)mut<<endl;
            mut++;
}

Also, I shortened your example little bite, because it contained some  unnecessary parts.
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Author Comment

by:Unimatrix_001
ID: 20370663
Thank you... :)
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LVL 53

Expert Comment

by:Infinity08
ID: 20372007
You could also do it as short as this :

        char c = 0;
        do {
          std::cout << (unsigned int) ((unsigned char) c) << std::endl;
        } while (++c);

or even :

        char c = 0;
        do {
          printf("%d\n", (unsigned char) c);
        } while (++c);
0
 
LVL 53

Expert Comment

by:Infinity08
ID: 20372030
or %u instead of %d ;)
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