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Common Enviroment for Windows and Mac

Posted on 2007-11-29
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Last Modified: 2010-03-30
In my program I am creating a zip file and FTP it to a server.  All that is working now, thanks to those who helped.  But my next problem is that my program is now running on a windows box so

   String target = "C:\\target.zip";

that works, but this program will also be running on Mac machines.  

Is there a standard ENV I can write and read the zip file from that will work on both platforms?
If so how would I go about setting it up?
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Question by:Jaziar
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3 Comments
 
LVL 17

Expert Comment

by:contactkarthi
ID: 20374083
you can use a properties file

or you can specify the source at the startup and use it in the program like

java myprgram "c:\\target.zip"
or
java myprogram "/usr/folder/target.zip"

inside the program in the main method get the path and use it

public static void main(String args[])
{
String path=args[0];
}
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Author Comment

by:Jaziar
ID: 20374194
I am a little confused

If I use

java myprgram "c:\\target.zip"
or
java myprogram "/usr/folder/target.zip"

would that cause the same problems I have now?  I need to be able to work on both platforms, whether it is mac or windows.  You're suggestion may be correct and I just don't understand it.  I am pretty new to java.
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Accepted Solution

by:
contactkarthi earned 500 total points
ID: 20375094
if you are running from windows use java myprgram "c:\\target.zip"

from linux use ava myprogram "/usr/folder/target.zip"

or you can do this

String path = null;
if (System.getProperty("os.name").toUpperCase().indexOf("WINDOWS") == -1) {
 path = "/usr/folder/target.zip";
}
else
{
 path="c:\\target.zip";
}
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