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Remove last characters of a string

Posted on 2007-11-30
4
Medium Priority
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2,733 Views
Last Modified: 2012-06-27
hi all,

I have a URL that I need to change.

It looks like this:

http://www.somewebsite/com/35445485448154_2b.jpg

I need to remove the "2b.jpg" at the end and replace it with "1b.jpg"

It's urgent...could you please help?

Thanks

ST3VO
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Question by:ST3VO
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4 Comments
 
LVL 28

Accepted Solution

by:
2266180 earned 2000 total points
ID: 20381124
if its' something else you're looking for, give more details.
function update_url(url, s:string):string;
var i:integer;
begin
  i:=pos('_', url);
  assert(i>0);
  delete(url, i+1, length(url));
  result:=url+s;
end;
 
....
update_url('http://www.somewebsite/com/35445485448154_2b.jpg', '1b.jpg');
....

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0
 

Author Comment

by:ST3VO
ID: 20381173
Why isn't this working??? Edit box it now being updated!
function update_url(url, s:string):string;
var i:integer;
begin
  i:=pos('_', url);
  assert(i>0);
  delete(url, i+1, length(url));
  result:=url+s;
end;
 
procedure TForm1.Button1Click(Sender: TObject);
var s, new: string;
begin
s:=Edit1.Text;
update_url(s,'1b.jpg');
Edit1.Text:=(s);
 
end;

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0
 
LVL 28

Expert Comment

by:2266180
ID: 20381201
update_url is a funciton not a procedure. which means it returns the modified string as a result. basically this allows you to use it nicely in one line like below ;)
procedure TForm1.Button1Click(Sender: TObject);
begin
  Edit1.Text:=update_url(edit2.text,'1b.jpg');
end;

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0
 

Author Closing Comment

by:ST3VO
ID: 31411890
Perfect!!! Thanks! :o)
0

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