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Having trouble starting to code c++ address book

Posted on 2007-12-01
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Last Modified: 2010-05-02
Hey guys, I am having a bit of trouble starting to write a contact book program in c++. I need to use an array on structures on this one, one for every contact. I plan to have an array of integers consisting of 1s and 0s, so that when I write the file out to a binary file, I can check whether the contact at that point in the array has a 1 for write or a 0 for don't add when writing.

 My questions so far are how would I be able to find what position in the array I am contact wise if I were to read in a previous contact book. ie contact[20] or contact [11] so that I would not override perviously entered contacts. Also, am I even reading in the information right? Thanks for your help

#include <iostream>

#include <fstream>
 

using namespace std;
 
 
 

void addContact();

void updateContact();

void deleteContact();

void printContacts();

void searchContact();
 

int main()

{

	

	string fileName;

	int menuChoice;

	fstream fileData;

	struct birthdate

	int writeOrNot[250];

	int counter = 0;

	{

		int date;

		int month;

		int year;

	};

	struct contactParameter

	{

		char name[50];

		char cellPhoneNumber[50];

		char emailAddress[50];

		birthdate birthday;

		enum personalOrBusiness

		{

			personal,

			business

		};

		personalOrBusiness pOrBType;

		

	};		

	contactParameter contact[250];

	

	cout << "Please enter the name of the file holding your address book.\n\n";

	cin >> fileName;

	fileData.open(fileName.c_str());

	

	
 

	cout << "Welcome to the address book application. Please select a task from the menu.\n\n"

		 << "1) Add a new contact \n\n2) Update a contact's informantion \n\n3) Delete a contact \n\n"

		 << "4) Search for a contact by name or address \n\n5) Print personal or business contacts in"

		 << " aplphabetical order by name\n\n 6) Exit the Program"; 

		

	 cin >> menuChoice;

	 switch(menuChoice)

	 {

		case 1:

			addContact();

			break;

		case 2:

			updateContact();

			break;

		case 3:

			deleteContact();

			break;

		case 4:

			searchContact();

			break;

		case 5:

			printContacts();

			break;

		case 6:

			exit(1);

			break;

		default:

			cout << "You have entered an invalid choice, please enter a valid integer based on your menu choice.";

			main();

			break;

	 }

}
 

void addContact()

{

	cout << "To create a new contact, enter the appropriate information as you are prompted. If you are unsure of something,"

	     << " just press enter.\n\n";

	cout << "Name?\n\n";

	cin.getline(contact[counter].name,50);

	cout << "Cellphone number?\n\n";

	cin.getline(contact[counter].cellPhoneNumber,50);

	cout << "Email address?\n\n";

	cin.getline(contact[0].emailAddress,50);

	cout << "Birthday day?\n\n";

	cin.getline(contact.birthday.date,50);

	cout << "Birthday month?\n\n";

	cin.getline(contact.birthday.month,50);

	cout << "Birthday year?\n\n";

	cin.getline(contact.birthday.year,50);

	cout << "Contact type?\n\n";

	cin.getline(contact.contactType,50);

	contact++;

	

	

}
 

void updateContact()

{

	

}
 

void deleteContact()	

{
 

}
 

void searchContact()

{
 

}
 

void printContact()

{
 

}

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Question by:pacman32689
  • 2
3 Comments
 

Author Comment

by:pacman32689
Comment Utility
Would a statement like this find what is the next blank spot in the address book?
	for(int i = 0; i< 250; i++)

	{

		if(contact[i].name == 0)

		{

			count = i;

		}

	}

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Accepted Solution

by:
Jaime Olivares earned 250 total points
Comment Utility
you should put the struct declaration outside the main() function.
Inside your main struct, you can use a boolean value to determine if the struct data is valid or should be saved:

      struct contactParameter
      {
                                bool validData;    // <------------- add this
            char name[50];
            char cellPhoneNumber[50];
            char emailAddress[50];
            birthdate birthday;
            enum personalOrBusiness {personal, business};
            personalOrBusiness pOrBType;
      };            

so you can evaluate as:
                 for (int i = 0; i< 250; i++)
      {
            if (!contact[i].validData)
            {
                  count = i;
                  break;   // don't continue searching
            }
      }
0
 

Author Closing Comment

by:pacman32689
Comment Utility
Thanks!
0

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