Learn how to a build a cloud-first strategyRegister Now

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 1257
  • Last Modified:

Having trouble starting to code c++ address book

Hey guys, I am having a bit of trouble starting to write a contact book program in c++. I need to use an array on structures on this one, one for every contact. I plan to have an array of integers consisting of 1s and 0s, so that when I write the file out to a binary file, I can check whether the contact at that point in the array has a 1 for write or a 0 for don't add when writing.

 My questions so far are how would I be able to find what position in the array I am contact wise if I were to read in a previous contact book. ie contact[20] or contact [11] so that I would not override perviously entered contacts. Also, am I even reading in the information right? Thanks for your help

#include <iostream>
#include <fstream>
 
using namespace std;
 
 
 
void addContact();
void updateContact();
void deleteContact();
void printContacts();
void searchContact();
 
int main()
{
	
	string fileName;
	int menuChoice;
	fstream fileData;
	struct birthdate
	int writeOrNot[250];
	int counter = 0;
	{
		int date;
		int month;
		int year;
	};
	struct contactParameter
	{
		char name[50];
		char cellPhoneNumber[50];
		char emailAddress[50];
		birthdate birthday;
		enum personalOrBusiness
		{
			personal,
			business
		};
		personalOrBusiness pOrBType;
		
	};		
	contactParameter contact[250];
	
	cout << "Please enter the name of the file holding your address book.\n\n";
	cin >> fileName;
	fileData.open(fileName.c_str());
	
	
 
	cout << "Welcome to the address book application. Please select a task from the menu.\n\n"
		 << "1) Add a new contact \n\n2) Update a contact's informantion \n\n3) Delete a contact \n\n"
		 << "4) Search for a contact by name or address \n\n5) Print personal or business contacts in"
		 << " aplphabetical order by name\n\n 6) Exit the Program"; 
		
	 cin >> menuChoice;
	 switch(menuChoice)
	 {
		case 1:
			addContact();
			break;
		case 2:
			updateContact();
			break;
		case 3:
			deleteContact();
			break;
		case 4:
			searchContact();
			break;
		case 5:
			printContacts();
			break;
		case 6:
			exit(1);
			break;
		default:
			cout << "You have entered an invalid choice, please enter a valid integer based on your menu choice.";
			main();
			break;
	 }
}
 
void addContact()
{
	cout << "To create a new contact, enter the appropriate information as you are prompted. If you are unsure of something,"
	     << " just press enter.\n\n";
	cout << "Name?\n\n";
	cin.getline(contact[counter].name,50);
	cout << "Cellphone number?\n\n";
	cin.getline(contact[counter].cellPhoneNumber,50);
	cout << "Email address?\n\n";
	cin.getline(contact[0].emailAddress,50);
	cout << "Birthday day?\n\n";
	cin.getline(contact.birthday.date,50);
	cout << "Birthday month?\n\n";
	cin.getline(contact.birthday.month,50);
	cout << "Birthday year?\n\n";
	cin.getline(contact.birthday.year,50);
	cout << "Contact type?\n\n";
	cin.getline(contact.contactType,50);
	contact++;
	
	
}
 
void updateContact()
{
	
}
 
void deleteContact()	
{
 
}
 
void searchContact()
{
 
}
 
void printContact()
{
 
}

Open in new window

0
pacman32689
Asked:
pacman32689
  • 2
1 Solution
 
pacman32689Author Commented:
Would a statement like this find what is the next blank spot in the address book?
	for(int i = 0; i< 250; i++)
	{
		if(contact[i].name == 0)
		{
			count = i;
		}
	}

Open in new window

0
 
Jaime OlivaresCommented:
you should put the struct declaration outside the main() function.
Inside your main struct, you can use a boolean value to determine if the struct data is valid or should be saved:

      struct contactParameter
      {
                                bool validData;    // <------------- add this
            char name[50];
            char cellPhoneNumber[50];
            char emailAddress[50];
            birthdate birthday;
            enum personalOrBusiness {personal, business};
            personalOrBusiness pOrBType;
      };            

so you can evaluate as:
                 for (int i = 0; i< 250; i++)
      {
            if (!contact[i].validData)
            {
                  count = i;
                  break;   // don't continue searching
            }
      }
0
 
pacman32689Author Commented:
Thanks!
0

Featured Post

Technology Partners: We Want Your Opinion!

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

  • 2
Tackle projects and never again get stuck behind a technical roadblock.
Join Now