Solved

sql 2005 query

Posted on 2007-12-03
3
250 Views
Last Modified: 2010-03-19
HI all,
i have table with
employeeid number
timein datetime
timout datetime

how can i calculate total punched hours. how can i calculate it timeout is null

the sample data i am giving.
empid   storeid      punchin                  punchout
2      1      2007-07-18 18:44:26.897      NULL
95      1      2007-08-22 17:20:04.373      NULL
2      5      2007-08-21 08:00:00.000      2007-08-21 10:00:00.000
2      5      2007-08-21 20:43:17.387      2007-08-22 11:08:40.343
59      7      2007-10-02 15:10:00.000      2007-10-02 18:56:44.973
62      7      2007-09-08 09:15:00.000      2007-09-08 19:30:00.000
62      7      2007-09-17 09:21:00.000      2007-09-17 17:00:00.000
0
Comment
Question by:romeiovasu
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
3 Comments
 
LVL 8

Expert Comment

by:srafi78
ID: 20399436
Select empid, storeid, sum(hours) from
(Select empid, storeid, Case when punchout is null then 0 else
DateDiss(hours , punchin, punchout) end as hours from employee)A
group by empid, storeid
0
 
LVL 8

Accepted Solution

by:
srafi78 earned 250 total points
ID: 20399445
Oops typo
Select empid, storeid, sum(hours) from
(Select empid, storeid, Case when punchout is null then 0 else
DateDiff(hour , punchin, punchout) end as hours from employee)A
group by empid, storeid
0
 
LVL 35

Assisted Solution

by:David Todd
David Todd earned 250 total points
ID: 20399701
Hi,

I'd suggest that instead of taking the datediff by hours that you do it in minutes else get only whole hours. And the amount of hours isn't whole hours as the code snippet shows.

Of course if you want hours you'll have to divide the minutes by 60, but you know that.

Cheers
  David
use tempdb
go
 
declare @StartDate datetime
declare @EndDate datetime
 
select 
	@StartDate = '2007-12-04 11:55:00'
	, @EndDate = '2007-12-04 12:05:00'
 
select 
	datediff( hour, @StartDate, @EndDate ) as hours
	, datediff( minute, @StartDate, @EndDate ) as mins
	

Open in new window

0

Featured Post

Secure Your Active Directory - April 20, 2017

Active Directory plays a critical role in your company’s IT infrastructure and keeping it secure in today’s hacker-infested world is a must.
Microsoft published 300+ pages of guidance, but who has the time, money, and resources to implement? Register now to find an easier way.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
SQL Job Hung 17 37
Rebooting Witness SQL Server 2 25
Convert time stamp to date 2 56
SQL Query - Multiple match on field with no extras 7 13
For both online and offline retail, the cross-channel business is the most recent pattern in the B2C trade space.
In this article we will learn how to fix  “Cannot install SQL Server 2014 Service Pack 2: Unable to install windows installer msi file” error ?
Via a live example, show how to setup several different housekeeping processes for a SQL Server.
Viewers will learn how the fundamental information of how to create a table.

733 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question