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Importing Dates from Strings in "DD-MMM-YYYY HH.NN.SS.ssss" Format

Hello,

I have a data file that I receive daily from another source.  I cannot change the format of the datafile.  I need to import the contents of the file into my SQL database (MS SQL Server 2000), and then perform various analyses.  Two of the fields are datetime fields in the format: "DD-MMM-YYYY HH.NN.SS.ssss".  I need the fields to be true datetime fields in my database.

A simple CAST or CONVERT gives me an error, saying that the string could not be converted to a date, presumably because of the month being in MMM format?

Is there a way to manipulate these date strings so that they can be properly imported?
0
gethryn
Asked:
gethryn
2 Solutions
 
wizengamotCommented:
The short answer is YES.  SQL supports the full ISO date / time format.  If your can modify your time string to meet the following standard

1995-12-31 23:59:59 or in other words YYYY-MM-DD HH:MM:SS

You can lop off what you don't need, so if say you don't want seconds, just don't include it in your string and it will be assigned a value of 00.  You cannot lop off from the other end but I don;t think you would want to lose the year value anyways.

Please note that the values range from large to small.  If the value is exactly as I have listed it here, it can be inserted into a datetime field in sql 2000 with no troubles.  This standard is the ISO 8601 date standard.  I have written a function in vb.net to peform this task for me but due to copyright laws with where I work I cannot post it as is, and I do not have a copy that I have written on my own time yet.  

The statement that would insert this into a database datetime field follows in the code block.
Insert Into MyTable (Currentdate) Values('1995-12-31 23:59:59')

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Ted BouskillSenior Software DeveloperCommented:
Actually it was the time that caused a problem on my system.  See the following.
DECLARE @s CHAR(25)
SET @s = '01-JAN-2007 13.13.13.1313'
 
--PRINT CONVERT(DATETIME, @s) -- Fails
PRINT CONVERT(DATETIME, LEFT(@s,11))+CONVERT(DATETIME, LEFT(RIGHT(REPLACE(@s,'.',':'),13),12))

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