Dice code modification Question

Posted on 2007-12-03
Last Modified: 2008-02-01
The code below works for finding 5, 4, 3 and a pair for dice and compare hands. Now I would like to add a small and large straight and full house..(like a yahtzee hand). I plan on writing methods for the straights and full house...but my questions are:

1. Where would I need to add this in existing code.
2. I assume I would have to once determining either straight or flush I would have to assign a value for it...What would be good?

Some comments appreciated...
public class FiveDice3
  public static void main(String[] args)
     final int NUM = 5;
     Die[] comp = new Die[NUM];
     Die[] player =  new Die[NUM];
     int x;
     for(x = 0; x < NUM; ++x)
        comp[x] = new Die();
        player[x] = new Die();
     int compMatch, playerMatch;
     int compHigh, playerHigh;
     String computerName = "Computer";
     String playerName = "You";
     display(computerName, comp, NUM);
     display(playerName, player, NUM);
     compMatch = howManySame(comp, NUM);
     playerMatch = howManySame(player, NUM);
     compHigh = compMatch / 10;
     playerHigh = playerMatch / 10;
     compMatch = compMatch % 10;
     playerMatch = playerMatch % 10;
     if(compMatch == 1)
       System.out.println("Computer has nothing");
       System.out.println("Computer has " + compMatch + " of a kind");
     if(playerMatch == 1)
       System.out.println("You have nothing");
       System.out.println("You have " + playerMatch + " of a kind");
     if(compMatch > playerMatch)
        System.out.println("Computer wins");
        if(compMatch < playerMatch)
           System.out.println("You win");
          if(compHigh > playerHigh)
            System.out.println("Computer's values are higher - computer wins");
            if(compHigh < playerHigh)
               System.out.println("Your values are higher - you win");
              System.out.println("It's a tie");
  public static void display(String who, Die[] die, int num)
     int x;
     String dice = "";
     for(x = 0; x < num; ++x)
        dice = dice + die[x].getValue() + " ";
     System.out.println(who + " rolled: " + dice);
  public static int howManySame(Die[] die, int num)
     int[] same = new int[num];
     int x, y;
     int highest;
     int highValue = 0;
     for(x = 0; x < num; ++x)
       same[x] = 1; // every die matches itself
     for(x = 0; x < num - 1; ++x)
       for(y = x + 1; y < num; ++y)
         if(die[x].getValue() == die[y].getValue())
             if(die[x].getValue() > highValue)
                highValue = die[x].getValue();
     highest = same[0];
     for(x = 1; x < num; ++x)
        if(same[x] > highest)
          highest = same[x];
     highest = highest + 10 * highValue;
     return highest;
public class Die
  private int value;
  private static final int HIGHEST_DIE_VALUE = 6;
  private static final int LOWEST_DIE_VALUE = 1;
  public Die()
    value = ((int)(Math.random() * 100) % HIGHEST_DIE_VALUE +
  public int getValue()
    return value;

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Question by:CPlusJavaCSharp
LVL 86

Expert Comment

ID: 20402018
Excuse my ignorance, but how do you get a flush in dice - there are no suits..?
LVL 92

Accepted Solution

objects earned 350 total points
ID: 20402043
1. add a method (or define an interface and a class) for each check thats required.
2. value them based on their rank

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