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MSSQL 2005 - Decimal column query

Posted on 2007-12-04
8
Medium Priority
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792 Views
Last Modified: 2008-02-01
Hi,

select mydecimalcolumn
from mytable

gives me:
10.05
4.25
4.5
4.0

How can I make a query that gives me data having a fracture more than 1 letter
10.05
4.25

Thank you.
0
Comment
Question by:Endelm
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8 Comments
 
LVL 18

Expert Comment

by:Jinesh Kamdar
ID: 20401905
You can convert it into a char and select only those records whose string-length following the decimal point (.) is greater than 1.
0
 
LVL 5

Accepted Solution

by:
nicolasdiogo earned 2000 total points
ID: 20401907
you can use a convert statement for that:


declare @d decimal(10,6)

set @d = 13.2452435


select @d
select convert( decimal (10, 2), @d )
0
 
LVL 23

Expert Comment

by:Ashish Patel
ID: 20401920
Try this.

select mydecimalcolumn
from mytable
where mydecimalcolumn*10 <> Round(mydecimalcolumn*10,0)
0
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LVL 25

Expert Comment

by:imitchie
ID: 20401938
select mydecimalcolumn
from mytable
where (mydecimalcolumn * 100) % 10 <> 0
0
 
LVL 25

Expert Comment

by:imitchie
ID: 20401942
take that last one back. try this

select mydecimalcolumn
from mytable
where cast(mydecimalcolumn as decimal(10,1) <> mydecimalcolumn)

one op only, which is cast to 1dp, so should be quite fast
0
 
LVL 6

Expert Comment

by:Rajesh_mj
ID: 20401973
Based On Imitchie's code,
select mydecimalcolumn
from mytable
where cast(mydecimalcolumn as decimal(10,1) < mydecimalcolumn)

Open in new window

0
 
LVL 6

Expert Comment

by:Rajesh_mj
ID: 20401984
sorry the mistake. i am take back my post
0
 
LVL 5

Expert Comment

by:ursangel
ID: 20410157
select mydecimalcolumn from Mytable
where len(mydecimalcolumn) - charindex('.', mydecimalcolumn) >= 2
0

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