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DOS batch file to determine Windows 2000 version

Posted on 2007-12-04
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Last Modified: 2010-04-21
I came across this DOS batch file in my search for a way to determine the Windows version:

@echo off

ver | find "2003" > nul
if %ERRORLEVEL% == 0 goto ver_2003

ver | find "XP" > nul
if %ERRORLEVEL% == 0 goto ver_xp

ver | find "2000" > nul
if %ERRORLEVEL% == 0 goto ver_2000

ver | find "NT" > nul
if %ERRORLEVEL% == 0 goto ver_nt

echo Machine undetermined.
goto exit

:ver_2003
:Run Windows 2003-specific commands here.
echo Windows 2003
goto exit

:ver_xp
:Run Windows XP-specific commands here.
echo Windows XP
goto exit

:ver_2000
:Run Windows 2000-specific commands here.
echo Windows 2000
goto exit

:ver_nt
:Run Windows NT-specific commands here.
echo Windows NT
goto exit

:exit
pause

I haven't found out yet whether or not Vista can be included in the script.

However, to me this is not important in this specific situation. I only need to know if people are running Windows 2000 or not so I can probably just delete the other versions, which thereby will de directed to "Machine undetermined".

But it would be nice to expand the script to also distinguise between:

2000 Professional
2000 Server
2000 Advanced Server
2000 Datacenter Server

Does anyone have an idea how to make that work? I tried adding the word "Professional" and the number "5.00.2195" in the batch file, but that didn't work ("Machine undetermined").

Greetings

Sebastian
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Question by:sebastianemborg
3 Comments
 
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Accepted Solution

by:
souseran earned 125 total points
ID: 20404537
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by:Bozwell99
Bozwell99 earned 125 total points
ID: 20404572
If you know the specific version number that that you want you can do it like this:

VER | find "Windows [Version 5.2.3790]" > nul

for Windows Server 2003 SP1, or:

VER | find "XP [Version 5.1.2600]" > nul

for Windows XP SP1

I don't have a Windows 2000 server to test on, but these work with My XP and 2003 PCs. Basically whatever appears when you use the 'VER' command on a PC is what you use for the version name you are looking for.
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Author Closing Comment

by:sebastianemborg
ID: 31412622
You both proved very helpful, thank you. Adding "5.00.2195" did the trick.
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