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XML & Java / org.w3c.dom; How to get only direct child nodes. (no grandchildern)

Posted on 2007-12-04
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Last Modified: 2008-02-01
Given the attached XML.

Suppose I'm at the outer most node. I want to get a NodeList of the childern of my current node named `A` but only direct children.

This should behave similar to the getElementsByTagName("A") method.


<A>
  <A>
  </A>
  <A>
  <A>
  </B>
  </B>
  <A>
    <A> <!-- I Don't want this one. -->
    </A>
  </A>
</A>

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Question by:modsiw
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5 Comments
 
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CEHJ earned 2000 total points
ID: 20405240
Probably easiest to use XPath. That would be pattern

./A
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Author Comment

by:modsiw
ID: 20405407
Looks good. =)

Below seems to be the common usage of XPath. Please confirm?

It looks like it always uses the Document itself as the starting point of the query. Is there anyway to get it to use another node as the start point for the query?


String strQuery = "something";
XPathFactory factory = XPathFactory.newInstance();
XPath xpath = factory.newXPath();
XPathExpression expr = xpath.compile(strQuery);
NodeList nList = (NodeList)expr.evaluate(doc, XPathConstants.NODESET);

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by:modsiw
ID: 20405456
Never mind my last. Stupid question. I read examples / tutorials and not docs.

Thanks much CEHJ. I believe this will work nicely.

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Expert Comment

by:CEHJ
ID: 20405577
:-)
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Author Comment

by:modsiw
ID: 20405618
Can I use multiple XPath`s to make multiple XPathExpression`s?

If so, (And I presume I can), what would be the reason for making multiple XPath`s from a single factory?
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