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How to get negative values to work with To_Number?

Posted on 2007-12-04
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Last Modified: 2011-10-03
I have the following code snippet. It works when the value in the variable TotalDue is 0 or greater. However if TotalDue has a negative value, it returns 0 instead of the correct value. For instance, if TotalDue is 100 and Sum_Memo is 50, it will return 50. However, if TotalDue is -100, then instead of returning -150, it returns 0. TotalDue and SumMemo are string variables. How can I fix it so it will show the correct value. incidentally, the colon in front of the variable just indicates that it an external variable, it does not have any bearing on the final result.

SELECT
To_Char(NVL(To_Number(:TotalDue),0) - NVL(To_Number(:Sum_Memo),0),'999,999.99')
INTO :TotalDuePrint
FROM dual

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Question by:geeta_m9
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8 Comments
 
LVL 13

Expert Comment

by:anand_2000v
ID: 20405842
try
SELECT
To_Char(NVL(To_Number(:TotalDue),0) - NVL(To_Number(:Sum_Memo),0),'MI999,999.99')
INTO :TotalDuePrint
FROM dual

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0
 

Author Comment

by:geeta_m9
ID: 20405935
I cannot use that format, I obtain an "Invalid Number Format Model."
0
 
LVL 13

Expert Comment

by:anand_2000v
ID: 20406001
What do you get if you try
SELECT
NVL(To_Number(:TotalDue),0) - NVL(To_Number(:Sum_Memo),0)
INTO :TotalDuePrint
FROM dual

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0
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Author Comment

by:geeta_m9
ID: 20406057
The value in the TotalDue has commas in it, i.e. 2,000 and I believe that is what is affecting the output. How do  I strip out the commas from TotalDue using SQL.
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LVL 13

Expert Comment

by:anand_2000v
ID: 20406084
try
SELECT
NVL(To_Number(replace(:TotalDue,',')),0) - NVL(To_Number(:Sum_Memo),0)
INTO :TotalDuePrint
FROM dual
0
 

Author Comment

by:geeta_m9
ID: 20406150
That works! Thank you! However, I need to get it in the format 9,999.99. How can I include that in the statement?
0
 
LVL 13

Expert Comment

by:anand_2000v
ID: 20406163
That should work now.
0
 
LVL 13

Accepted Solution

by:
anand_2000v earned 500 total points
ID: 20406175

SELECT
To_Char(NVL(To_Number(replace(:TotalDue,',')),0) - NVL(To_Number(replace(:Sum_Memo,',')),0),'999,999.99')
INTO :TotalDuePrint
FROM dual

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0

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