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How do I return records from a date range with SQL syntax?

Posted on 2007-12-04
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Last Modified: 2010-05-18
I have an SQL table of records from 2006-2007 and I want to select a range of records based upon start and stop dates entered into text boxes.

I'm using Visual Web Developer; SQL Express; Express Management Studio; VB backcoding

Here's my statement:

SELECT [ID], [BILLNUMBER], [CHARGEDATE], [LNAME], [FNAME] FROM [TABLETracking] WHERE (([CHARGEDATE] IS NOT NULL) AND ([CHARGEDATE] >= @CHARGEDATE) AND ([CHARGEDATE] <= @CHARGEDATE2) AND ([7CAT] = @7CAT))


So, the @CHARGEDATE and @CHARGEDATE2 values are coming from textbox dates that are entered. @7CAT is a value from a user-select dropdown list.

However, a start and stop date such as 01/01/2007 to 12/31/2007 will also return records from the year 2006 (arrrghhhh!...frustrating). How can I make this work? I know there is a BETWEEN statement that can be used, but I am unable to get anything to work..... maybe my parentheses are not structured correctly. Thanks for any assistance.
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Question by:jazjef
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6 Comments
 
LVL 3

Expert Comment

by:cforant
ID: 20406280
SELECT column_name FROM table_name
WHERE column_name
BETWEEN value1 AND value2
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LVL 23

Accepted Solution

by:
Ashish Patel earned 500 total points
ID: 20406447
Try this.
SELECT [ID], [BILLNUMBER], [CHARGEDATE], [LNAME], [FNAME] FROM [TABLETracking] WHERE [CHARGEDATE] IS NOT NULL AND [CHARGEDATE] BETWEEN @CHARGEDATE AND @CHARGEDATE2 AND [7CAT] = @7CAT

0
 
LVL 4

Author Comment

by:jazjef
ID: 20406575
asvforce:

thanks for the reply... your statement works fine, but I still get records from 2006 when I use it.
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LVL 23

Expert Comment

by:Ashish Patel
ID: 20406617
What is the column type of CHARGEDATE column?
0
 
LVL 4

Author Comment

by:jazjef
ID: 20406853
ASVFORCE:

column type was char(10)

this was causing the problem.... when I converted to datetime your solution works.... and so does my own original solution prior to asking the question.... thanks.

I have another problem though.... I will post a question on it momentarily. It's related to this datetime thing...
0
 
LVL 23

Expert Comment

by:Ashish Patel
ID: 20406865
Good catch!!! Glad to hear that you have solved this now.
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