Trim function not working

Are you sure you don't have carriage returns in fldMfrnum?  They can often look like trailing spaces until you expand the height of the rows when viewing the data in the table.

ok...that may be it ?

how do i get rid of them.. please

Can you tell which character it is from this ?

fldMfrnum
22119  
22251  
23028  
23116  
23484  
23485  
23701  
24065  
24577  
24581  
24583  
24585  
24683  
24829  
25024  

Select allOpen in new window

chr 13 and 10   not doing it... ?

Thanks

Is the datatype on the field numeric or text?

you will need replace function

replace([fldMfrnum]," ","")

or
just use

trim(val([fldMfrnum]))

UPDATE tblData SET tblData.fldMfrnum = Replace([fldMfrnum], Chr(160),"");


It was a non breaking space...?

did you try

UPDATE tblData SET tblData.fldMfrnum = trim(val([fldMfrnum]))

Going back to the beginning, what was the problem?  You have a string with trailing blanks you want to get rid of.  Most things suggested here will do that.  Then what?

Gray l,

Going back to the beginning, what was the problem?  

I have a field with data.
at the end of the last character there are what appear to be carriage returns or spaces...
1 or 2 sometimes 3
You have a string with trailing blanks you want to get rid of.  Most things suggested here will do that.  
Then what?
I was testing out different chr(<character>)   chr(160)  seemed to get rid of the spaces..?
I have never come acrosss this chr  before..

cactus data   suggestion  did not work either...
Without suggesing a explicit  chr(160)..

Capricorn1 suggestion worked fine...
UPDATE tblData SET tblData.fldMfrnum = trim(val([fldMfrnum]))

But I would like to know why it catches chr(160) ??

Thanks for ALL the comments

Capricorn1 suggestion worked fine...
UPDATE tblData SET tblData.fldMfrnum = trim(val([fldMfrnum]))

<But I would like to know why it catches chr(160) ??>

trim(val([fldMfrnum]))

val([fldMfrnum])   ->> retrieves all numeric characters starting from position 1 and stops at the position of the first non numeric character

so using val in a string like
val(12345Xdj 4578 amwhatever character ) returns  12345

val(A123456) returns 0

capricorn,  one small glitch...

It if the entry is a alphanumric or   alpha      ABC123A   OR   BUSSMANN

IT SETS THE ENTRY TO  "0"

i just posted it above..

well, you have to consider all the the data formats of a field before you can use a working codes.

my codes was based on the sample data you posted

what do you want to do with this type of data

{ ABC123A   OR   BUSSMANN }

if you want to remove special characters from a field of mixed type of data,
you will need a function to do that

something like this

Function CleanString(sString As String) As String

    Dim sReturn As String, i
    sReturn = ""
    For i = 1 To Len(sString)
        If (Asc(Mid(sString, i, 1)) >= 32 And Asc(Mid(sString, i, 1)) <= 127) Then
           sReturn = sReturn & Chr(Asc(Mid(sString, i, 1)))

        End If
    Next i
    CleanString = Trim(sReturn)
   
End Function

the same thing,
but if the spaces(or carriage returns or whatever(spaces)) exist after the last character or digit...it  gets rid of them..
The data format in this field is  "text". It will always be "Text".

Yes, the data I showed just happend to come that way to me..
Sorry for the confusion to all  !!

Thanks Cap...

Then fall back to Replace:

UPDATE tblData SET tblData.fldMfrnum = Replace([fldMfrnum], Asc(160), "");
or:
UPDATE tblData SET tblData.fldMfrnum = Trim(Replace([fldMfrnum], Asc(160), ""));

/gustav

Sorry, Chr():

UPDATE tblData SET tblData.fldMfrnum = Trim(Replace([fldMfrnum],Chr(160),""));

/gustav

cap, On your function what about capturing the   chr(160)   ?

that function eliminates all  that is not within the scope of chr(32) - chr(127)


what do you mean  by
<what about capturing the  chr(160)   ?>

if instr(fieldname,chr(160))>0 then
      'what do you want to do with chr(160)?
     
end if

cap,
if instr(fieldname,chr(160))>0 then
      'what do you want to do with chr(160)?

get rid of the space  just like the others..

did you try the function i posted above?

Utilizing the function ...thanks to all....

better use this function to get values 0-9 A-z

Function CleanString(sString As String) As String

    Dim sReturn As String, i
    sReturn = ""
    For i = 1 To Len(sString)
        If (Asc(Mid(sString, i, 1)) >= 48 And Asc(Mid(sString, i, 1)) <= 57) _
            Or (Asc(Mid(sString, i, 1)) >= 65 And Asc(Mid(sString, i, 1)) <= 90) _
            Or (Asc(Mid(sString, i, 1)) >= 97 And Asc(Mid(sString, i, 1)) <= 122) Then
           sReturn = sReturn & Chr(Asc(Mid(sString, i, 1)))
            Else
            'Debug.Print Asc(Mid(sString, i, 1))
        End If
    Next i
    CleanString = Trim(sReturn)
   
End Function