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PHP alternating table colors in table - populated from string

Posted on 2007-12-05
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Last Modified: 2012-06-27
Would very much appreciate some suggestions on the following:

I have a string which is being read from a MySQL field.
The string is the contents of an excel spreadsheet but it contains simplified form of BB code, which I use a series of str_replace() to convert to an HTML table.

That part works OK

My roblem is that I need to alternate the BG color in the table and as I don't always know how many rows there wil be I can't hard code the colou.

I thought that if I used explode() to turn the string in to an array with each each value of the array being a row of the table and the contents of the table being echoed via a "for" loop which ran the color change script it would work ...... but no luck.

Following is a code snippet so that you see what I mean.

Thanks
<?php
 
// I set the colour variables
$color1 = "#C5AE9E"; 
$color2 = "#D2C1B5";  
$ $row_count = 0;
 
// here is the string that will become the HTML table
// this is just a rogh example of it
$string = "[Otitle]    Starters    [Ctitle]            
[Odish]    Garlic Bread     [Cdish]    [Oprice]    7.00    [Cprice]
[Odish]    Bruschetta    [Cdish]    [Oprice]    7.50    [Cprice]
[Odish]    Nico's Salad    [Cdish]    [Oprice]    9.00    [Cprice]";
 
// again just an example - this time of the str_replace() section
 
$string = str_replace("[Otitle]", "<tr bgcolor='colourMyRow'> <td><strong>", $string);  
$string = str_replace("[Ctitle]", "</strong></td></tr> %^&*", $string); 
 
// now to convert the string into an Array using the un needed "%^&*" text 
 
$myArray = explode("%^&*", $string);
 
 
// here I count the total values in the Array and start the loop
$arrayCounted = sizeof($myArray);
for ($i=0;$i<=$arrayCounted;$i++){
 
// this should alternate my colours
  $row_colour = ($row_count % 2) ? $color1 : $color2;  
 
// this should assign the colour to each row in the table
    $menuArray [$i] = str_replace("colourMyRow", "$row_colour", $menuArray[$i]);  
 
$row_count++;      
  
  echo ($myArray[$i]);                                                                             
} 
 
// as I said before, everything but the colour change works
?>

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Question by:pepenuro
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4 Comments
 
LVL 24

Expert Comment

by:glcummins
ID: 20411547
The problem appears to be here:

$ $row_count = 0;


Try changing that to:

$row_count = 0;
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LVL 5

Accepted Solution

by:
nacker2000 earned 250 total points
ID: 20413456
Hi,

Try the following code:
<?php
	// I set the colour variables
	$color1 = '#C5AE9E';
	$color2 = '#D2C1B5'; 
	$row_count = 0;
 
	// here is the string that will become the HTML table
	// this is just a rogh example of it
	$string = "[Otitle]    Starters    [Ctitle]            
	[Odish]    Garlic Bread     [Cdish]    [Oprice]    7.00    [Cprice]
	[Odish]    Bruschetta    [Cdish]    [Oprice]    7.50    [Cprice]
	[Odish]    Nico's Salad    [Cdish]    [Oprice]    9.00    [Cprice]";
 
	// again just an example - this time of the str_replace() section
	$string = str_replace("[Otitle]", "<tr bgcolor='colourMyRow'> <td><strong>", $string);  
	$string = str_replace("[Ctitle]", "</strong></td></tr> %^&*", $string); 
 
	// now to convert the string into an Array using the un needed "%^&*" text 
	$myArray = explode("%^&*", $string);
 
	foreach($myArray as $row){
		// this should alternate my colours
		$row_count++;
		$row_colour = ($row_count % 2) ? $color1 : $color2;  
		 
		// this should assign the colour to each row in the table
		$row = str_replace('colourMyRow', $row_colour, $row);     
		
		// output 
		echo($row);                                                                             
	} 
 
	// as I said before, everything but the colour change works
?>

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Author Closing Comment

by:pepenuro
ID: 31412846
Worked perfectly the first time.
I had included a typo in my question ($ $row_count = 0;
) apologies but that was just  typo in the copy and pasting for the snippet.

Many thanks!!
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LVL 5

Expert Comment

by:nacker2000
ID: 20414616
Glad I could help :)
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