how can i traverse and edit each xml node data using vb.net

Hi

Is there any code in vb.net that traverse through each and every node allow us to change on any specific. I need to traverse each node if exist and their child nodes if exist and need to modify that specific node content. e.g. US to United States
Xml sample:

 <GATE>
  <GAT>Q</GAT>
  <GA>Mon</GA>
    <DEST>
     <GR>
       <GC>15</GC>
       <GN>All</GN>
      </GR>
      <GR>
        <GC>15</GC>
        <GN>Cuba</GN>
          <DES>
            <DE>
                <DC>15</DC>
                <DN>US</DN>
            </DE>
          </DES>
      </GR>
    </DEST>
 </GATE>

Regardless of how deep the xml is ..i need to traverse each node and its child node and so on ... any vb.net code sample would help me

Thanks
Shaukat

shwaqar82Asked:
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PaulHewsConnect With a Mentor Commented:
Something like this should work:

Imports System.Xml
Public Class Form1

    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        Dim xmlDoc As New XmlDocument
        xmlDoc.Load("C:\temp\test.xml")  'To your xml file or url... if its a string, use  xmldoc.LoadXml

        TraverseFixNodes(xmlDoc.DocumentElement)

        xmlDoc.Save("C:\temp\new.xml")  'Save fixed file

    End Sub

    'recursive sub to traverse and change text of nodes
    Private Sub TraverseFixNodes(ByVal node As XmlNode)
        If node.InnerText = "US" Then node.InnerText = "United States"
        For Each childNode As XmlNode In node.ChildNodes
            TraverseFixNodes(childNode)
        Next
    End Sub

End Class
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Geert BormansConnect With a Mentor Information ArchitectCommented:
I would use an XSLT

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:template match="*">
        <xsl:copy>
            <xsl:copy-of select="@*"/>
            <xsl:apply-templates select="node()"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="text()">
        <xsl:choose>
            <xsl:when test=". = 'US'">United States</xsl:when>
            <xsl:otherwise><xsl:value-of select="."/></xsl:otherwise>
        </xsl:choose>
    </xsl:template>
</xsl:stylesheet>

cheers

Geert
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PaulHewsCommented:
One other quickie method... If you have the XML in a string variable, you can use the string methods:

xmlString = xmlString.Replace("US", "United States")
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PaulHewsCommented:
But that could be dangerous if the text searched for is in the tags of the nodes and not in the data.... I would not use this unless I knew exactly what the possibilities were.
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Geert BormansInformation ArchitectCommented:
> xmlString = xmlString.Replace("US", "United States")

make it xmlString = xmlString.Replace(">US<", ">United States<")
to be sure it is only in element content
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Computer101Commented:
Forced accept.

Computer101
EE Admin
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