Solved

special join between 3 tables

Posted on 2007-12-05
5
211 Views
Last Modified: 2010-03-20
I need a query to find an totals for items and writeins for each company.  I have an Order table, an Orderdetails table, and a OrderWritein table.  Both OrderDetails and OrderWriteIns have a Price and Quantiy column.  I wrote this with joins as follows:
Select C.CompanyName,sum(D.price*D.Quantity) itmAmt,sum (W.price*W.Quantity) wiAmt,max(O.OrderDate) [Last Order]
From tblOrders O
Inner Join tblCompany C on O.companyid = C.companyid
Inner Join tblOrdersDetail D on O.orderid=D.orderid
Inner Join tblOrdersWriteIns W on O.orderid=W.orderid
group by C.companyName

The problem is when I join the write in table it does a cross join.  if I have 10 items and 10 writeIns then the sum is for the 100 rows.  How do I write the query so each company has the correct sum for both itemsDetail and writeIns?
0
Comment
Question by:moraleskp
  • 4
5 Comments
 
LVL 25

Expert Comment

by:imitchie
ID: 20416613
Select C.CompanyName,
 (select sum(D.price*D.Quantity) from tblOrdersDetail D where O.orderid=D.orderid) itmAmt,
 (select sum (W.price*W.Quantity) from tblOrdersWriteIns W where O.orderid=W.orderid) wiAmt,
 max(O.OrderDate) [Last Order]
From tblOrders O
Inner Join tblCompany C on O.companyid = C.companyid
group by C.companyName
0
 
LVL 25

Accepted Solution

by:
imitchie earned 125 total points
ID: 20416624
this will work better..
Select OC.CompanyName,
 (select sum(D.price*D.Quantity) from tblOrdersDetail D where OC.orderid=D.orderid) itmAmt,
 (select sum (W.price*W.Quantity) from tblOrdersWriteIns W where OC.orderid=W.orderid) wiAmt,
 OC.[Last Order]
From (
 select C.CompanyName, max(O.OrderDate) [Last Order]
 FROM tblOrders O
 Inner Join tblCompany C on O.companyid = C.companyid
 group by C.companyName
) OC

Open in new window

0
 

Author Comment

by:moraleskp
ID: 20417054
imitchie,
Thanks for responding.
on the first response I got an error saying orderid was not in the group by clause.
In the second response got an error that orderId is an invalid column.  I guess because it is not selected in the sub query.
Your responses gave me some ideas so I tried the following code.  It seems to work.  



select companyName,sum(itmAmt),sum(wiAmt),max(Orderdate)
from
(Select O.orderid,C.CompanyName,
(select sum(D.PriceSold*D.qty) from tblOrdersDetail D where O.orderid=D.orderid)itmAmt,
(select sum(W.RetailPrice*W.Qty) from tblOrders_Writeins W where O.orderid=W.orderid) wiAmt,
O.orderdate
from tblOrders O
inner join tblCompany C on O.companyid=C.companyid
Group by C.companyName,O.orderid,O.orderdate
) query
group by companyName
Order by CompanyName

Open in new window

0
 
LVL 25

Expert Comment

by:imitchie
ID: 20417073
You are right. Good on you to find a solution! This would probably have worked, and does less work

Select OC.CompanyName,
 (select sum(D.price*D.Quantity) from tblOrdersDetail D where OC.orderid=D.orderid) itmAmt,
 (select sum (W.price*W.Quantity) from tblOrdersWriteIns W where OC.orderid=W.orderid) wiAmt,
 OC.[Last Order]
From (
 select O.OrderID, C.CompanyName, max(O.OrderDate) [Last Order]
 FROM tblOrders O
 Inner Join tblCompany C on O.companyid = C.companyid
 group by C.companyName
) OC
0
 
LVL 25

Expert Comment

by:imitchie
ID: 20417077
nvm, orderid is not in the group by..
0

Featured Post

Master Your Team's Linux and Cloud Stack

Come see why top tech companies like Mailchimp and Media Temple use Linux Academy to build their employee training programs.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
SQL Server 2012 r2 - Varible Table 3 31
What's wrong with this T-SQL Foreign Key? 7 51
convert null in sql server 12 46
Mysql Left Join Case 10 70
In this article I will describe the Copy Database Wizard method as one possible migration process and I will add the extra tasks needed for an upgrade when and where is applied so it will cover all.
This article describes how to use the timestamp of existing data in a database to allow Tableau to calculate the prior work day instead of relying on case statements or if statements to calculate the days of the week.

840 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question