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If statement accepting a through z only... need help!

Posted on 2007-12-06
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Last Modified: 2007-12-09
I need help with this code I need my if statement to accept a through z only and if a number or something else is entered it would fall into the else statement. When I entered a word if goes into the else I do not know what it is doing this.

Here is what I have for this file:
#include <iostream>

#include <string>

#include <fstream>

#include "game.h"

 

#define MaxWordSize 10

#define MaxWords 50

typedef char String[MaxWordSize];

String Words[MaxWords - 1];

int Count;

char Word[MaxWordSize];

int Size;

int Loop;

Game myGame;

 

using namespace std;

 

void Game::addWord()

{

    myGame.loadFile();

    ofstream Datfile("words.txt");

try

{

    cout << "\tEnter a new word, keep it below " << MaxWordSize << " characters: ";

    cin >> Word;

	if(Word == "ABCDEFGHIJKLMNOPQRSTUVWXYZ")

	{

    Size = strlen(Word);

 

    strcpy_s(Words[Count++],MaxWordSize,Word);

 

    for (int i = 0; i < Count; ++i) Datfile << Words[i] << endl;

	}

	else

	{

		throw 1;

	}

}

	catch(int e)

	{

		cout << "Error...\n";

	}

}

void Game::deleteWord()

{

	cout << "you have chosen to delete a word...\n";

}

 

void Game::loadFile()

{

	char C;

	ifstream Datfile;

 

	Count = 0;

 

	Datfile.open("words.txt");

 

	while((C=Datfile.peek()) !=EOF)

	{

		Datfile >> Words[Count++];

 

		if(Count > MaxWords - 1)

		{

			cout << "\nToo many words in the file, stopping with " << MaxWords << " words." << endl;

			Count = MaxWords;

			break;

		}

	}

 

	Count--;

 

	Datfile.close();

}

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Question by:jschmuff
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8 Comments
 
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Accepted Solution

by:
Jaime Olivares earned 300 total points
ID: 20425122
>>      if(Word == "ABCDEFGHIJKLMNOPQRSTUVWXYZ")

this won't work at all, you can design your own function, so you can use  like:

      if(validateWord(Word))

Here is the validating funcion:


// this will require: #include <stdio.h>
 

bool validateWord(char *word)

{

       for (int i=0; word[i]; i++)

            if (!isletter(word[i])

                  return false;

       return true;

}

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Author Comment

by:jschmuff
ID: 20425168
what does that have to do with taking the input only a through z?
0
 
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Expert Comment

by:Jaime Olivares
ID: 20425181
it validates if all characters in Word are A though Z and returns you a boolean value.
your code:
if(Word == "ABCDEFGHIJKLMNOPQRSTUVWXYZ")
doesn't work as you expected and always return false, so exception will never occur.
0
 
LVL 55

Expert Comment

by:Jaime Olivares
ID: 20425186
sorry, in this case, exception will always occur.
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Author Comment

by:jschmuff
ID: 20425202
so that is something that would be done before the if statement since if(validateWord(Word)) is that correct.
so to actually do a - z I have to use a for loop? What is the isletter in this example you have given me? cause it is something that will need to be declared.
0
 

Author Comment

by:jschmuff
ID: 20425211
Is there another way this can be done like if(number is input) { throw 1; } else then the code to add and save word to file.. catch blah blah blah?
0
 
LVL 55

Expert Comment

by:Jaime Olivares
ID: 20425236
>>so that is something that would be done before the if statement since if(validateWord(Word)) is that correct
validateWord is a separate function.

>>so to actually do a - z I have to use a for loop?
yes, you have to use a loop

>>What is the isletter in this example you have given me
isletter is a function declared in the stdio.h header, it test if a character is a letter or not. But you can use isalpha instead, it is more compatible.
If you don't want to use it, you can do this instead:


bool validateWord(char *word)

{

       char c; 

       for (int i=0; c = word[i]; i++)

            if (!(c>='A' && c<='Z') && !(c>='a' && c<='z'))

                  return false;

       return true;

}

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Assisted Solution

by:evilrix
evilrix earned 200 total points
ID: 20434994
use std::string::find_first_not_of: -

http://www.cppreference.com/cppstring/find_first_not_of.html
char const * Word = "qwerty"; // Your word!
 

if(std::string::npos != std::string(Word).find_first_not_of("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"))

{

	throw std::runtime_error("Invalid data");

}

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