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How to access control from the GridView

Hello guys,

I have several templated columns and a button control in the GridView.

On GridView_RowCommand() when user clicks on the button I need to get values from the 2 Label controls on the GridView.

How can I reach these Labels. I tried GridView1.FindControl["lblCustomerID"] but It is incorrect...

Please advice.

boro_bob

Can you show us the exact code you are using when you do the GridView1.FindControl?

Sachintana Dissanayake

You have to first get the GridViewRow using the e.CommandSource.
Then find the control which is in the GridViewRow.

See the sample code below.

    protected void GridView_RowCommand(object sender, GridViewCommandEventArgs e)
    {
        if (e.CommandName == "ButtonCommandName")
        {
            GridViewRow row = (GridViewRow)((Control)e.CommandSource).Parent.Parent;
            Label labelValue = (Label)row.FindControl("lblCustomerID");
        }
    }

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boro_bob

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alik13

ASKER

Thank you guys for Help!

Based on your suggestions I figured it out.

The code line :

GridViewRow row = (GridViewRow)((Control)e.CommandSource).Parent.Parent;

does not work for me, because my GridView located inside the AJAX UpdatePanel, but

I figured out the solution & it works! So, please use this if you have your GridView inside an AJAX UpdatePanel and you need to get some values from the GridView controls in response to the OnRowCommand event when the Button is clicked. It is a good choice when you do not need to be redirected to another page (No need for QueryString)

Here the code:

protected void dgProviders_RowCommand(object sender, GridViewCommandEventArgs e)
{

if (e.CommandName.Equal("ButtonCommandName"))
{
// *** Retreive the DataGridRow
int row = -1;

int.TryParse(e.CommandArgument as string, out row);

if (row == -1)
{
this.ErrorDisplay.ShowError("Invalid selection...");
return;
}

GridViewRow selectedRow = gvCustomers.Rows[row];

Label lblCustomerID = (Label)row.FindControl("lblCustomerID");

String customerID = lblCustomerID.Text;
}
}

Sachintana Dissanayake

Good Luck!!!