asked on

Regex between brackets

I just need to use regex to remove allbetween the brackets and the brackets themselves.

so

$string = 'this is the text (hello all)';

this is the text

lexshine

ASKER

can I start awarding myself 500 points??

$str = "not between brackets (between brackets)";
echo preg_replace("/([a-z0-9_\-]+)\s+$.+$/i", "\\1", $str);

ddrudik

Before you finalize the question, you might consider:
echo preg_replace('/$[^)]*$/','',$string);
Or to remove any spaces (horizontal/veritcal/etc.) before the first parens:
echo preg_replace('/\s*$[^)]*$/','',$sourcestring);

lexshine

ASKER

Well one thing I didnt mention is it needed to work in a smarty template parse statement which the one I posted does.

{$thedata.rtitle|regex_replace:"/([a-z0-9_\-]+)\s+$.+$/i":"\\1"}

can yours work in this scenario?

ddrudik

I don't have a way of testing that, I guess you could try:
{$thedata.rtitle|regex_replace:"/\s*$[^)]*$/":""}

And let me know if that worked for you.

lexshine

ASKER

Yes, that did actually work.

Is that a better approach than the one I pasted. Can you explain the difference between the 2?

ddrudik

My pattern finds the () groups (and any spaces before them) and replaces what's found with an empty string. In general, the shorter and less complex (fewer match groups etc.) the patterns, the more efficient.

ASKER CERTIFIED SOLUTION

ddrudik

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ddrudik

Thanks for the question and the points.