Passing on URL variables in PHP

On this page: http://samsonhairrestoration.com/scratch/zoomify/image_gallery/5.php?name=craig_e&shoot=0&file=1&zm=28 

I have a bunch of URL variables. I would like to click on the Full Screen link on the top and

go to the fullsize version of the image on this page: http://samsonhairrestoration.com/scratch/zoomify/image_gallery/full.php?name=craig_e&shoot=0&file=1&zm=28

The variables are identical. Just have to pass them from one page to the next.

I vaguely recall that in ASP one has to store the variables on the first page, in a hidden form field? I can't recall for sure and never done it in php.

What's the fastest, easiest way to do this in php?
polaatxAsked:
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hieloConnect With a Mentor Commented:
OK. Try this:
echo('<a href="http://samsonhairrestoration.com/scratch/zoomify/image_gallery/full.php?name=' . $_REQUEST['name'] .' &shoot=' . $_REQUEST['shoot'] . '&file=' . $_REQUEST['file'] . '&zm=' . $_REQUEST['zm'] . '">Full Screen</a>');

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hieloCommented:
Modify the "Full screen" URL on this page so that its url point to:
http://samsonhairrestoration.com/scratch/zoomify/image_gallery/full.php?name=craig_e&shoot=0&file=1&zm=28

So instead of:
<a href="#">Full Screen</a>

You would need:
<a href="http://samsonhairrestoration.com/scratch/zoomify/image_gallery/full.php?name=craig_e&shoot=0&file=1&zm=28">Full Screen</a>
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polaatxAuthor Commented:
Hello, I made a mistake in explaining myself.

This is going to be a DYNAMIC link, so can't hardcode.

What I need to to grab the URL that loads 5.php page (the first page) and build a new URL where the is replaced with the URL of fullscreen page.

So
5.php?name=craig_e&shoot=0&file=1&zm=28

would become

full.php?name=craig_e&shoot=0&file=1&zm=28

What is the best way to do that? Use URL Parse?
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polaatxAuthor Commented:
thank you so much.

Question: why did you use _REQUEST instead of _GET ?
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