Expand (x-1)(x-2)...(x-n)
The solution to a problem is P(x) = (x-1)(x-2)...(x-n) (for some integer n).
However, I want to expand this polynomial, so as to find the coefficient of the ith power.
It's quite clear that: a_n=1, and a_0=n!(-1)^n, but I've yet to figure a pattern for the others...
How would I approach this?
Thanks
However, I want to expand this polynomial, so as to find the coefficient of the ith power.
It's quite clear that: a_n=1, and a_0=n!(-1)^n, but I've yet to figure a pattern for the others...
How would I approach this?
Thanks
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wow! didn't knew about these stirling triangles!
anyway, no equation compute them stright forward.
anyway, no equation compute them stright forward.
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ASKER
Wow
see this link
http://en.wikipedia.org/wiki/Pascal's_triangle