Haha guys, I have an elementary physics question I just want to make sure my understanding is correct.
Let's say I throw an object up perfectly vertical in the absence of air resistance. Time until impact back on the ground is 6 seconds. Let us also assume g = 9.80 m/s^2
Since we have no idea what displacement, Vi or Vf is, I assume the only equation I can use algebraically is
v = at
Substituting in my knowns I get...
v = (-9.81)(6)
However, That would return a - for my initial velocity. Almost v= at does not distinguish between vi and vf from what I can see. What am I doing wrong, or is there a resource that can guide me? Thanks guys.