LEECHIPTURNER
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CALCULATING ACREAGE ON UNEQUAL SIDES
I have a piece of property that is 315 ft 8 inches, 165 ft, 236 ft, and 128 ft 2 in. How many acres is that? And how do I calculate it?
Thanks!
Thanks!
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ASKER CERTIFIED SOLUTION
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My diagram 3 is a little confusing. The diagonal line, which I labelled S, is NOT the same s used in heron's formula, which is the semi-perimeter of a scalene triangle. Don't confuse the two!
ASKER
AWESOME! You folks are amazing. Attached is the actual diagram. I have an added anomaly in that the front of the shape is slightly curved.
PLOT.jpg
PLOT.jpg
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from that diagram, and assuming that the angles at the base are both 90 degrees, the area is close to 45516.90 sq feet
165.00 * 236.06 = 38949.9
1/2 * 165 * 79.60 = 6567
total = 45516.9 sq feet = 1.04 acres
that may be slightly on the low side, as the street boundary has a small curvature, which would incread the total area by perhaps a couple of sq feet.
AW
</DO NOT ACCEPT THIS FOR POINTS>
from that diagram, and assuming that the angles at the base are both 90 degrees, the area is close to 45516.90 sq feet
165.00 * 236.06 = 38949.9
1/2 * 165 * 79.60 = 6567
total = 45516.9 sq feet = 1.04 acres
that may be slightly on the low side, as the street boundary has a small curvature, which would incread the total area by perhaps a couple of sq feet.
AW
</DO NOT ACCEPT THIS FOR POINTS>
ASKER
Thanks Arthur for the final answer. And thanks to all for helping me understand how to do it in the future!!
ignoring the curvature, 165 * (236.06+315.66)/2 = 45516.9
Ohh .. the two triangle solution is much more elegant.
Thanks!
Thanks!
Do you know the angles at the corners? Are any of the sides parallel?