asked on
C# main class instance
I have a doubt in the following code why we have to create the instance
of the same class like below
TestDelegateClass tdc = new TestDelegateClass();
in the given code.
My doubt is we have to create instance if there are two classes but here are having only one class
Please clarify me..
of the same class like below
TestDelegateClass tdc = new TestDelegateClass();
in the given code.
My doubt is we have to create instance if there are two classes but here are having only one class
Please clarify me..
public delegate Boolean MyDelegate(Object sendingobj, Int32 x);
public class TestDelegateClass
{
Boolean MyFunction(Object sendingobj, Int32 x)
{
//Perform some processing
return (true);
}
public static void main(String [] args)
{
//Instantiate the delegate passing the method to invoke in its constructor
MyDelegate mdg = new MyDelegate(MyFunction);
// Construct an instance of this class
TestDelegateClass tdc = new TestDelegateClass();
// The following line will call MyFunction
Boolean f = mdg(this, 1);
}
}
C#Programming Languages-Other
Last Comment
JRumana
ASKER
Ok... if i comment the line
// TestDelegateClass tdc = new TestDelegateClass();
then the above program will work or not? please clarify me.
// TestDelegateClass tdc = new TestDelegateClass();
then the above program will work or not? please clarify me.
ASKER CERTIFIED SOLUTION
THIS SOLUTION ONLY AVAILABLE TO MEMBERS.
View this solution by signing up for a free trial.
Members can start a 7-Day free trial and enjoy unlimited access to the platform.
ASKER
Now i got it thanks for your help
The answer is you don't already have an instance of the class. The static keyword modifying the main method allows the method to be called without instantiating the class. Static methods behave the same way no matter what class they're in. It's just a fancy way of organizing methods. Consider how the Math class has functions for Cos and Sin. You don't need to instantiate a new Math object in order to call these functions as they require no instance information to give you an appropriate result.
Hope that helps.