Start Free Trial
Come for the solution, stay for everything else.
Start Free Trial
Can someone explain me how can i find the three first terms of maclaurin series for that equation:
square root (1+x) [in other words : 1+x ^ (1/2) ]
Thanks in advance for any help !
Math / Science
8/22/2022 - Mon
take the derivative three times
1 + 1/2 x^2 - 1/8 x^4
Sorry, I meant
1 + 1/2 x - 1/8 x^2
Experts Exchange has (a) saved my job multiple times, (b) saved me hours, days, and even weeks of work, and often (c) makes me look like a superhero! This place is MAGIC!
ASKER CERTIFIED SOLUTION
Log in or sign up to see answer
Become an EE member today
7-DAY FREE TRIAL
Members can start a 7-Day Free trial then enjoy unlimited access to the platform
Sign up - Free for 7 days
Learn why we charge membership fees
We get it - no one likes a content blocker. Take one extra minute and find out why we block content.
See how we're fighting big data
Not exactly the question you had in mind?
Sign up for an EE membership and get your own personalized solution. With an EE membership, you can ask unlimited troubleshooting, research, or opinion questions.
ask a question
Note that the link I posted contains the exact same information, so I'm wondering why you chose to not accept it ?
Note: Plus signs and minus signs mean different things.
1 + 1/2 x (one PLUS one half x, which is what you have) is NOT the same as 1 - x/2 (one MINUS one half x)
I think you're confusing me with ozo ;)
Take a look at the link I posted - note the image you posted is the same as the one in the link heh.
to EE for less than $4 a week.
Unlimited question asking, solutions, articles and more.
However, I included the actual answer. Which I feel is a little more respectable than slapping down a link and a wink face. But again, yes, I did mistake you for ozo.
Oh, I wasn't trying to belittle your reply - I merely wanted to know how perdoname_'s decision was made, so I can learn and give better answers next time :)
Plans and Pricing
Certified Expert Program
© 1996-2022 Experts Exchange, LLC. All rights reserved. Covered by US Patent