troubleshooting Question

print field if/else

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nascent1Flag for Canada asked on
PHP
4 Comments1 Solution188 ViewsLast Modified:
I want to have the surname print and if there is also an entry in "web", then I want to print the surname as a link using the address stored in "web". The final output should look like this, depending on whether or not there is something in "web".

Dr. Who
or
<a href="www.who.com">Dr. Who</a>
if ($selectlinks3['name'] !== '')
    {
           echo "<strong>{$selectlinks3['name']}&nbsp;</strong>";
    }
		if ($selectlinks3['surname'] !== '')
    {
           echo "<strong>{$selectlinks3['surname']}</strong>";
    }
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