troubleshooting Question

print field if/else

Avatar of nascent1
nascent1Flag for Canada asked on
4 Comments1 Solution188 ViewsLast Modified:
I want to have the surname print and if there is also an entry in "web", then I want to print the surname as a link using the address stored in "web". The final output should look like this, depending on whether or not there is something in "web".

Dr. Who
<a href="">Dr. Who</a>
if ($selectlinks3['name'] !== '')
           echo "<strong>{$selectlinks3['name']}&nbsp;</strong>";
		if ($selectlinks3['surname'] !== '')
           echo "<strong>{$selectlinks3['surname']}</strong>";
Join the community to see this answer!
Join our exclusive community to see this answer & millions of others.
Unlock 1 Answer and 4 Comments.
Join the Community
Learn from the best

Network and collaborate with thousands of CTOs, CISOs, and IT Pros rooting for you and your success.

Andrew Hancock - VMware vExpert
See if this solution works for you by signing up for a 7 day free trial.
Unlock 1 Answer and 4 Comments.
Try for 7 days

”The time we save is the biggest benefit of E-E to our team. What could take multiple guys 2 hours or more each to find is accessed in around 15 minutes on Experts Exchange.

-Mike Kapnisakis, Warner Bros