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peter_coopFlag for United Kingdom of Great Britain and Northern Ireland asked on

date format help needed

i have a mysql timestamp which is in the format

2008-05-29 11:00:14

i need it to display 29-05-2008 11:00:14

i have tried various codes, but cannot get it to display uk format. any help would be appreciated as it's driving me crazy. thanks
MySQL ServerPHP

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peter_coop

8/22/2022 - Mon
Guy Hengel [angelIII / a3]

the date_format() function should be able to do that:
http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html#function_date-format


DATE_FORMAT(your_column, '%d-%m-%Y %T')

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Aleksandar Bradarić

In PHP, you can use:
---
echo date('d-m-Y H:i:s', strtotime('2008-05-29 11:04:14'));
---
ASKER
peter_coop

i am having trouble seeing where to place this code in relation to the attached function. any help? thanks
function print_acts($act){
	$print .= '<table width="70%"  border="0" align="center">' . "<tr><td><strong><font color='#FF6600' size='6'>sample</font></strong></strong><br />sample<br /><hr><p><strong><font color='#000000' size='4'>ACTION CONTROL AREA</font></strong></strong></p></td></tr>" . '<br />' .'<table width="70%" border="1" align="center">' ."<tr bgcolor='#CCCCCC'><td><strong>Service</strong></td><td><strong>Customer</strong></td><td><strong>Department</strong></td><td><strong>Activity</strong></td><td><strong>Item</strong></td><td><strong>Date</strong></td><td><strong>Quantity</strong></td><td><strong>Type</strong></td><td><strong>Action</strong></td></tr>";
	$num=mysql_numrows($act) ;
	$i=0; 
	while ($i < $num) {
		$service = mysql_result($act,$i,"service");
		$company = mysql_result($act,$i,"company");
		$department = mysql_result($act,$i,"department");
		$activity = mysql_result($act,$i,"activity");
		$item = mysql_result($act,$i,"item");
		$date = mysql_result($act,$i,"date");
		$quantity = mysql_result($act,$i,"quantity");
		$type = mysql_result($act,$i,"type");
		$new = mysql_result($act,$i,"new");
		$print .= format_act($service,$company,$department,$activity,$item,$date,$quantity,$type,$new);
		$i++; 
	}
	$print .= "</table>";
	
	return $print;
}

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Aleksandar Bradarić

Here:
---
$date = date('d-m-Y H:i:s', mysql_result($act,$i,"date"));
---
Guy Hengel [angelIII / a3]

my suggestion would not go in that part of the code, but in the sql query that is used to fill the $act variable.
ASKER CERTIFIED SOLUTION
Aleksandar Bradarić

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ASKER
peter_coop

thanks once again
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