Format Time Difference

What is the best way to return the time difference in nn:hh format?

Is there a better way to write this statement?

SELECT DATEDIFF("n",#1:13:44#,#2:45:33#) & FORMAT(#2:45:33# - #1:13:44#,":ss")

Note that this will not work:
SELECT FORMAT(#2:45:33# - #1:13:44#,":ss")
because it will not return a value greater than 60 minutes.
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ThomasianAsked:
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peter57rCommented:
I don't really know what you mean by ' nn:hh format'.

If you want the time difference in hms then you can do:

FORMAT(#2:45:33# - #1:13:44#,"hh:mm:ss")
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ThomasianAuthor Commented:
Most of the difference will be less than 1 hour. If I use "hh:nn:ss", most of the values (if not all) returned will have a value 0. That is why I want to combine the hour and minute value.

e.g.
A difference of 1:30:12 will be returned as 90:12
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peter57rCommented:
You cannot show an minute value greater than 59. It would produce an invalid time value.

If you want to show the result like that you will have to do some calculations and create a string to display the value.

cstr(DATEDIFF("s",#1:13:44#,#2:45:33#) \60 ) & ":" & cstr(DATEDIFF("s",#1:13:44#,#2:45:33#)  mod 60 )
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ThomasianAuthor Commented:
Will that be better than the query I posted?

SELECT DATEDIFF("n",#1:13:44#,#2:45:33#) & FORMAT(#2:45:33# - #1:13:44#,":ss")
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peter57rCommented:
yes.
Datediff ("n",.......) will just look at the minute numbers so half the time you will get the wrong answer

DATEDIFF("n",#1:13:59#,#1:14:00#) gives 1 (minute)
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ThomasianAuthor Commented:
Thanks, I didn't notice that.
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