Solved

php mysql add days to date variable

Posted on 2008-06-10
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1,501 Views
Last Modified: 2008-06-10
trying to add a number of days variable to a date variable... here is what I have so far (not working):

$newDate = strtotme("+$days_to_add day", $existing_date());
echo "<br>Days added: $days_to_add";
echo "<br>New date: $newDate<br>";
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Question by:newbe101
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4 Comments
 
LVL 48

Expert Comment

by:hernst42
ID: 21752698
What is the content of $existing_date?

should lokk like this:
$newDate = strtotime("+$days_to_add day", $existing_date);
echo "<br>Days added: $days_to_add";
echo "<br>New date: $newDate<br>";
0
 

Author Comment

by:newbe101
ID: 21752743
$existing_date is a date pulled from my mysql database (0000-00-00).
here is my echo results:
Days added: 60 to 2008-06-08
New date: 5186008
I don't know why new date looks like that... shouldn't it be in the 0000-00-00 format?
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LVL 48

Accepted Solution

by:
hernst42 earned 500 total points
ID: 21752799
strtotime returns an unix timestamp which must be formated with date to your desired output

justreplace the hard coded things with your variables
echo date("Y-m-d", strtotime("2008-06-08 +5 days")) ."\n";

$newDate = date("Y-m-d", strtotime("$existing_date +$days_to_add day days"))
0
 

Author Comment

by:newbe101
ID: 21755520
perfect... thanks again!
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