Want to win a PS4? Go Premium and enter to win our High-Tech Treats giveaway. Enter to Win

x
Solved

# I need a function that could return me the day worked.

Posted on 2008-06-11
Medium Priority
159 Views
Hello guys

I need a function that could return me a quantity of days without weekend, since my first day of the month.

Thanks
0
Question by:hidrau
[X]
###### Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

• Help others & share knowledge
• Earn cash & points

LVL 26

Accepted Solution

Russell Libby earned 2000 total points
ID: 21763859
Give this a try, I believe it is pretty well tested. I wasn't sure if you were counting today in the result, or not (eg, if you consider today-yesterday = 2 days, or 1 day), so the function allows you to specify that.

As to the function, it determines how many weeks (full 7 days) have passed. That part is easy, because 7 days = 5. The remainer needs to be figured out based on day of the week that that the StartDate falls. (determine if the day count wraps into a weekend).

Regards,
Russell

----

function DaysWorkedSince(StartDate: TDateTime; IncludeToday: Boolean = False): Integer;
var  dwDay:         Integer;
dwTotal:       Integer;
dwWeeks:       Integer;
dwDays:        Integer;
begin

// Get the day of week for the starting day (0 = Sunday and 6 = Saturday)
dwDay:=DateTimeToTimeStamp(StartDate).Date mod 7;

// Subtract today and start date
dwTotal:=Trunc(Now - StartDate);

// Update by 1 if today should be included
if IncludeToday then Inc(dwTotal);

// Calculate the number of total weeks and remainder days
dwWeeks:=dwTotal div 7;
dwDays:=dwTotal mod 7;

// Weeks = 5 working days
result:=dwWeeks * 5;

// Check remainder days
if (dwDays > 0) then
begin
// Now figure in the days based on the starting date
case dwDay of
0  :  Dec(dwDays);
1  :  if (dwDays > 5) then dwDays:=5;
2  :  if (dwDays > 4) then dwDays:=4;
3  :
begin
if (dwDays = 6) then
dwDays:=4
else if (dwDays > 3) then
dwDays:=3;
end;
4  :
begin
if (dwDays > 3) then
Dec(dwDays, 2)
else if (dwDays = 3) then
dwDays:=2;
end;
5  :
begin
if (dwDays > 2) then
Dec(dwDays, 2)
else if (dwDays = 2) then
dwDays:=1;
end;
6  :
begin
if (dwDays > 2) then
Dec(dwDays, 2)
else
dwDays:=0;
end;
end;
// Update result
Inc(result, dwDays);
end;

end;

ShowMessage(IntToStr(DaysWorkedSince(StrToDate('5/1/2008'), True)));
0

LVL 1

Author Closing Comment

ID: 31466282
thanks

I tested and it is working.
If I have any problem I'll let you know
0

## Featured Post

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

The uses clause is one of those things that just tends to grow and grow. Most of the time this is in the main form, as it's from this form that all others are called. If you have a big application (including many forms), the uses clause in the in…
This article explains how to create forms/units independent of other forms/units object names in a delphi project. Have you ever created a form for user input in a Delphi project and then had the need to have that same form in a other Delphi proj…
Have you created a query with information for a calendar? ... and then, abra-cadabra, the calendar is done?! I am going to show you how to make that happen. Visualize your data!  ... really see it To use the code to create a calendar from a q…
In response to a need for security and privacy, and to continue fostering an environment members can turn to for support, solutions, and education, Experts Exchange has created anonymous question capabilities. This new feature is available to our Pr…
###### Suggested Courses
Course of the Month9 days, 12 hours left to enroll