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Cron job to delete folder/files older than n days.

Posted on 2008-06-11
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Last Modified: 2013-12-27
I need a simple script (cron... run daily) to do some cleanup on directories older than n days, but I need to leave the top directory intact.

So basically, I need to:

1) Get a list of all directories in my current directory (this dir will always be a year.. .2007, 2008, 2009)
2) cd to that directory and delete all directories (and files) below that are older than n days.

For instance, given the following structure:

/2007
/2007/mydir/
/2008
/2008/yourdir/

I would need to delete mydir and yourdir if they were older than n days, while leaving the top level directory alone.

This is on solaris unix.
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Question by:krussell222
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4 Comments
 
LVL 40

Expert Comment

by:omarfarid
ID: 21765894
try

cd /2007
find . -mtime +n -exec rm -rf {} \;


   
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Author Comment

by:krussell222
ID: 21766153
The thing is, I'm not going to know which year directories are going to be in here... and I don't want to have to change the code when we role over to 2009.  I'd like to be able to just kick it off and have it check each top level year directory.  
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LVL 40

Accepted Solution

by:
omarfarid earned 2000 total points
ID: 21766187
for name in `ls`
do
if [ -d $name ]
then
      cd $name
      find . -mtime +n -exec rm -rf {} \;
      cd ..
fi
done
0
 

Author Comment

by:krussell222
ID: 21766244
This is just about it.  The only thing missing is that I want the find/remove if the loop to only go one directory deep.  Unfortunately, Solaris doesn't have a maxdepth arg for find.  Maybe using prune or someting.
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