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Count certain fields in a record on what they contain - Access 2003

Posted on 2008-06-11
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Last Modified: 2013-11-28
I have an Access 2003 db and I want to create a report or form that does the following.

Reach record has about 15.

Field1, field2, field3 etc.

Field1  is Name
FIeld2  is a question with a reposne of Yes, No
Field3  is an other quesitons with a resonse option of yes  or no
etc. etc.

I want to be able to sumaries each record as to how many yes answers there are and how many no answers there are.

I tried somethign like this but it did not work - it gave me the amount of reocrds in the the table.
SELECT Table2.Answer, Count(Table2.Answer) AS [Count]
FROM Table2
GROUP BY Table2.Answer;
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Question by:Pdeters
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12 Comments
 
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Expert Comment

by:Missus Miss_Sellaneus
ID: 21764911
SELECT Table2.Answer, SUM(IIF(Table2.Answer = "yes",1,0)) AS [Count]
FROM Table2
GROUP BY Table2.Answer;
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Expert Comment

by:Missus Miss_Sellaneus
ID: 21764921
Sorry, I didn't count the No's.. try this one:

SELECT Table2.Answer, SUM(IIF(Table2.Answer = "yes",1,0)) AS [CountYes],
SUM(IIF(Table2.Answer = "no",1,0)) AS [CountNo],
FROM Table2
GROUP BY Table2.Answer;
0
 

Author Comment

by:Pdeters
ID: 21765851
This is what i am getting in the query

Headings            -Answer           CountYes            CountNo
Row                          Yes                 3                             0

This is what I am using

SELECT Table1.answer, Sum(IIf(Table1.Answer="yes",1,0)) AS CountYes, Sum(IIf(Table1.Answer="no",1,0)) AS CountNo
FROM Table1
GROUP BY Table1.answer;


There are 3 records with a total of 6 yes and 2 now
I need it to show 6 yes and 2 no
0
 

Author Comment

by:Pdeters
ID: 21765966
This is what I want it to show

Headings            -Answer           Count            
Row                          Yes                 6                            
                                   No                  2
 or


Headings            -Answer           Yes                            tNo
Row                          Yes                 6                            2


0
 

Author Comment

by:Pdeters
ID: 21766043
It is only counting the first field that has yes/no as an option .
How can I get it to count all the fields in the record that have yes/no options.
0
 

Author Comment

by:Pdeters
ID: 21766086
So for record1 should be 2 yes and 1 no
Record 2 shoulld have 2 yes and 1 no
Record 3 should have 2 yes and 0 no
0
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Expert Comment

by:Missus Miss_Sellaneus
ID: 21766189
What exactly does your original query do? You said it gives you the number of records instead of the count. It looks like it should work. Is this what it's giving you?

Answer    Count
Yes            6
No             6
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Expert Comment

by:Missus Miss_Sellaneus
ID: 21766201
I created my own table and tested your original query. It works here. I'm using Access 97.
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Author Comment

by:Pdeters
ID: 21767774
This is what it is giving me
Headings            -Answer           CountYes            CountNo
Row                          Yes                 3                             0

I am using Access 2003

Thisi s what I am looking for

This is what I want it to show

Headings            -Answer           Count            
Row                          Yes                 6                            
                                   No                  2
 or

Headings            -Answer           Yes                            tNo
Row                          Yes                 6                            2
0
 

Author Comment

by:Pdeters
ID: 21767813
It is only grabbing the yes and no from the first field in each record that has yes/no - am looking for it tor the yes/no from all the fields
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Accepted Solution

by:
Jeffrey Coachman earned 500 total points
ID: 21800195
Pdeters,

Try this

You can cheat a little and subtract the number Yes values from the total number of Yes/No Fields to get the count of the No values.
(See my query)

JeffCoachman
Access-EEQ23477771SummarizeMulti.mdb
0
 
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Expert Comment

by:Jeffrey Coachman
ID: 21800209
Pdeters,

But the Report should display what you asked for.

Jeff
0

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