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How do I write a regular expression to trim a complex path name

Posted on 2008-06-12
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Last Modified: 2008-06-13
I have a string with a path name eg. 'c:\microsoft\windows\shared'.  I want to pass this string to a reg exp and get the string 'c:\microsoft\windows' back from it.  How do I do this?

I got a good answer for this already.  However the regexp that I was given doesn't work on the type of path that name that I'm using.  The answer I got was :
            String sourcestring = @"c:\microsoft\windows\shared";
          String matchpattern = @"(.*)\\.*";
          String replacementpattern = @"$1";
          string bob = Regex.Replace(sourcestring, matchpattern, replacementpattern);
which does in fact return c:\microsoft\windows to bob.
however, the path I'm using is something like the following:  c:\.....\siteview\1.0.0.0__9f4da00116c38ec5
I need to trim the final folder of the path using a reg exp.
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Question by:millerthegorilla
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Expert Comment

by:ddrudik
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Please show what result you want and what result you get from the provided code.  Thanks.
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Author Comment

by:millerthegorilla
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I want back 'c:\....\siteview'

the provide code just returns the same string.
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Expert Comment

by:ddrudik
Comment Utility
Show the C# code you are using with your source string included so that I can test here.  In  the truncated example I don't see the issue:

Raw Match Pattern:

(.*)\\.*
 

Raw Replace Pattern:

$1
 

C#.NET Code Example:

using System;

using System.Text.RegularExpressions;

namespace myapp

{

  class Class1

    {

      static void Main(string[] args)

        {

          String sourcestring = "source string to match with pattern";

          String matchpattern = @"(.*)\\.*";

          String replacementpattern = @"$1";

          Console.WriteLine( Regex.Replace(sourcestring,matchpattern,replacementpattern));

        }

    }

}
 

$sourcestring after replacement:

c:\.....\siteview

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Author Comment

by:millerthegorilla
Comment Utility
here you go.  the variable location contains:
http://spdev/personal/administrator/_wpresources/SiteViewV4/1.0.0.0__9f4da00116c38ec5/

imageName is 'image1' etc
        private string getImageLocation(string imageName)

        {

            String matchpattern = @"(.*)\\.*";

            String replacementpattern = @"$1";

            string directory = @"images/";

            string rval = Regex.Replace(location, matchpattern, replacementpattern) + directory + imageName;

            return rval;

        

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Expert Comment

by:ddrudik
Comment Utility
If the source contains a trailing slash such as:
http://spdev/personal/administrator/_wpresources/SiteViewV4/1.0.0.0__9f4da00116c38ec5/

Please show what you want as the result text.
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Author Comment

by:millerthegorilla
Comment Utility
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Accepted Solution

by:
ghostdog74 earned 500 total points
Comment Utility
you don't need a regular expression. Sometimes its best to do things simple. You can split on slashes "\", then join them back, excluding the last field.
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