Solved

MSSQL query changed to MySQL shows not valid mysql resource

Posted on 2008-06-12
6
555 Views
Last Modified: 2008-08-05
Alright

I worked on this for hours and I'm stuck. Below I pasted the script from a working MSSQL login which I changed to use with MySQL. I know that there are syntax differences and the hours I spent was replacing some of them in this script but I've got no where.

I keep getting invalid mysql result resource. Usually on ($result=mysql_query($sql);) however it changes to other lines depending the script.

A fix would be great I'm assuming its a quick thing I cant believe I cant get it working from my MySql book and online!
session_start();

  $user="##";

  $host="##";

  $password="##";

  $database="##";

 

mysql_connect("$host", "$user", "$password")or die("cannot connect");

mysql_select_db("$database")or die("cannot select DB");
 

$sql="SELECT * FROM users WHERE username='$_POST[myusername]' AND pass='$_POST[mypassword]'";

$result=mysql_query($sql);

 

// mysql_num_row is counting table row

$count=mysql_num_rows($result);

// If result matched $myusername and $mypassword, table row must be 1 row

 

if($count==1) //Login details were found so auth

{

Open in new window

0
Comment
Question by:Ryan Bayne
  • 3
  • 3
6 Comments
 
LVL 17

Accepted Solution

by:
nanharbison earned 300 total points
ID: 21774686
If you are using variables for MySQL functions, don't use quotes. So change
mysql_connect("$host", "$user", "$password")
to
mysql_connect($host, $user, $password)
and change this:
$sql="SELECT * FROM users WHERE username='$_POST[myusername]' AND pass='$_POST[mypassword]'";

to this:
$sql="SELECT * FROM users WHERE username='".$_POST['myusername']."' AND pass='".$_POST['mypassword']."'";

because if you are using post and get variables you have to separate them from the code with a double quote and a dot. I also think you need to add single quotes to $_POST[myusername] inside the brackets, the way I did it in the changed version. I always forget if you HAVE to do it.
0
 
LVL 17

Expert Comment

by:nanharbison
ID: 21774689
the use of double and single quotes, and having to set off variables that are in the form $_POST[] and $_SESSION[], etc always slays me!
0
 
LVL 2

Author Comment

by:Ryan Bayne
ID: 21774799
Well your changes are correct and as you will see in my code below I needed to change the quotes.

I've arrived at a point I did reach myself prior to this question but ended up starting again maybe this time you can help me.

// mssql_num_row is counting table row
$count=mysql_num_rows($result);

That line results in... mysql_num_rows(): supplied argument is not a valid MySQL result resource in
I did think there was a different way to do this with mysql but I'm thinking I dreamed that up!

ideas? thanks so far
<?php

//Processes attempted login

//Retrieves users access permission and fowards to required page depending on that users authorisation

session_start();
 

  $user="##";

  $host="##";

  $password="##";

  $database="##";

 

mysql_connect($host, $user, $password)or die("cannot connect");

mysql_select_db("$database")or die("cannot select DB");
 

$sql='SELECT * FROM users WHERE username="$_POST[myusername]" AND pass="$_POST[mypassword]"';

$result=mysql_query($sql);

 

// mssql_num_row is counting table row

$count=mysql_num_rows($result);

// If result matched $myusername and $mypassword, table row must be 1 row
 

		

if($count==1 && $level=='closed')//Send to account closed page

{

	$_SESSION['auth']="yes";

	header("location: index.php?pagecell=closed.php");

}

else if($count==1 && $level=='master')//Send to web master page

{

	$_SESSION['auth']="yes";

	header("location: index.php?pagecell=admin/webmaster.php");

}

else if($count==1 && $level=='admin')//Send to basic admin area

{

	$_SESSION['auth']="yes";

	header("location: index.php?pagecell=closed.php");

}

else if($count==1 && $level=='member')//Send to member page

{

	$_SESSION['auth']="yes";

	header("location: index.php?pagecell=closed.php");

}

else

{

	header("location: index.php?cell=pagecells/loginfail.php");

	exit();

}
 

?> 

Open in new window

0
Microsoft Certification Exam 74-409

Veeam® is happy to provide the Microsoft community with a study guide prepared by MVP and MCT, Orin Thomas. This guide will take you through each of the exam objectives, helping you to prepare for and pass the examination.

 
LVL 2

Author Comment

by:Ryan Bayne
ID: 21774882
I think thats it done. Had to mess around with the quotes and stuff a bit more. Actually I better review what I done I cant remember lol

THANKS
<?php

//Processes attempted login

//Retrieves users access permission and fowards to required page depending on that users authorisation

session_start();
 

  $user="root";

  $host="localhost";

  $password="25130217cmt";

  $database="WebTG2008";

 

mysql_connect($host, $user, $password)or die("cannot connect");

mysql_select_db("$database")or die("cannot select DB");
 

$sql='SELECT * FROM users WHERE username="$_POST[myusername]" AND password="$_POST[mypassword]"';
 

$result=mysql_query($sql);

 

// mssql_num_row is counting table row

$count = mysql_num_rows($result);

// If result matched $myusername and $mypassword, table row must be 1 row
 

		

if($count==1 && $level=='closed')//Send to account closed page

{

	$_SESSION['auth']="yes";

	header("location: index.php?pagecell=closed.php");

}

else if($count==1 && $level=='master')//Send to web master page

{

	$_SESSION['auth']="yes";

	header("location: index.php?pagecell=admin/webmaster.php");

}

else if($count==1 && $level=='admin')//Send to basic admin area

{

	$_SESSION['auth']="yes";

	header("location: index.php?pagecell=closed.php");

}

else if($count==1 && $level=='member')//Send to member page

{

	$_SESSION['auth']="yes";

	header("location: index.php?pagecell=closed.php");

}

else

{

	header("location: index.php?cell=pagecells/loginfail.php");

	exit();

}
 

?> 

Open in new window

0
 
LVL 2

Author Comment

by:Ryan Bayne
ID: 21774888
oops put database details. dont worry its a test db only on testing environment with no data
0
 
LVL 17

Expert Comment

by:nanharbison
ID: 21777404
So you got the mysql_num_rows to work? You get that error when there is something wrong with the query or there is no data returned. You might be better off saying:
if ($count = mysql_num_rows($result)) {

      do something

}


0

Featured Post

U.S. Department of Agriculture and Acronis Access

With the new era of mobile computing, smartphones and tablets, wireless communications and cloud services, the USDA sought to take advantage of a mobilized workforce and the blurring lines between personal and corporate computing resources.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

A lot of articles have been written on splitting mysqldump and grabbing the required tables. A long while back, when Shlomi (http://code.openark.org/blog/mysql/on-restoring-a-single-table-from-mysqldump) had suggested a “sed” way, I actually shell …
Introduction In this article, I will by showing a nice little trick for MySQL similar to that of my previous EE Article for SQLite (http://www.sqlite.org/), A SQLite Tidbit: Quick Numbers Table Generation (http://www.experts-exchange.com/A_3570.htm…
With the power of JIRA, there's an unlimited number of ways you can customize it, use it and benefit from it. With that in mind, there's bound to be things that I wasn't able to cover in this course. With this summary we'll look at some places to go…
Hi friends,  in this video  I'll show you how new windows 10 user can learn the using of windows 10. Thank you.

867 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

16 Experts available now in Live!

Get 1:1 Help Now