Why my array output is wrong

PHP

Why my array output is wrong

i have this code in code snippet

my result should be
supermarketname | Amount_of_candy | Amount_of_milo | AMount_of_milk |...
    coles       |    1.00000      |   5.00000         |    2.00000     |...
    target      |    5.00000      |  10.00000      |    3.00000     |...
...
   
but i get result as below
      
coles | "1.00000"|target| "5.00000"| parkson| "2.00000"... and so on

other words my amount become
coles | array[0] | target | array[1] | parkson | array[2] .. and so on

this is so wrong as you can see from my code GetAmount(()

coles should follow by array[0],array[1] and array[2]

but dont know why array[1] has go to target which is wrong
how to do this?

function GetAmount()
{
$ItemID = array(1234,6545,5468,9856,"no stock",4561,5466);
$arrayElement[3] = "no stock";
$supermarketID = 21;
 
 $i = 0;
 $j = 0;
 
 for ($j = 0; $j < sizeof($ItemID); $j++)
  {
 if (($ItemID[$j] != $arrayElement[3]) 
	{
	 $query = "SELECT getitem_std_amount( \"$supermarketID\",  \"ItemID[$j]\") AS AMOUNT";
     
	 $result = mysql_query($query);
     if(!$result) die("Query didn't work. " . mysql_error());
    
     $temp = "";   	 
     while($row = mysql_fetch_array($result))
	      {
            $temp = '"'.$row['AMOUNT'].'"';
              } 
              $this->GetAmountReturn[$i++] .= $temp ; 
              }	 
   	}  
	else
    {
      $this->GetAmountReturn[$i] .=  "\"Full Time Employees\" |";
  	  $i++;
	}
   }
 
 Wishing you a very happy birthday and a year full of things you love 
function joinSUPERMARKETNAMEnAMOUNT()
{
//SUPERMARKETNAME select value is from another function
 
 foreach(($this->GetSupermarketNameReturn_value as $i => $SupermarketName)
	{
         $data1 = "{$SupermarketName} | {$this->GetAmountReturn[$i]}  "; 
	  print_r( $data1);
	 }
        }  
}

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firekiller15Asked:
Who is Participating?
 
Bernard S.Connect With a Mentor CTOCommented:
Looking at << $query = "SELECT getitem_std_amount( \"$supermarketID\",  \"ItemID[$j]\") AS AMOUNT";>>
and using the sample data you are testing with
$ItemID = array(1234,6545,5468,9856,"no stock",4561,5466);
$arrayElement[3] = "no stock";
$supermarketID = 21;

The first run will give SELECT getitem_std_amount( "21",  "1234") AS AMOUNT;
The second SELECT getitem_std_amount( "21",  "5454") AS AMOUNT;
and 5th one SELECT getitem_std_amount( "21",  "no stock") AS AMOUNT;

What is precisely the result of running $result = mysql_query($query) ?


0
 
hernst42Commented:
Try replacing

              $this->GetAmountReturn[$i++] .= $temp ;
              }  
        }  
        else
    {
      $this->GetAmountReturn[$i] .=  "\"Full Time Employees\" |";
          $i++;
        }
with

              $this->GetAmountReturn[$j] .= $temp ;
              }  
        }   else    {
      $this->GetAmountReturn[$j] .=  "\"Full Time Employees\" |";
        }
0
 
firekiller15Author Commented:
change it to $j doesnt make any different?
0
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hernst42Commented:
please post the modified code
0
 
firekiller15Author Commented:
function GetAmount()
{
$ItemID = array(1234,6545,5468,9856,"no stock",4561,5466);
$arrayElement[3] = "no stock";
$supermarketID = 21;
 
 
 
 for ($j = 0; $j < sizeof($ItemID); $j++)
  {
 if (($ItemID[$j] != $arrayElement[3])
      {
       $query = "SELECT getitem_std_amount( \"$supermarketID\",  \"ItemID[$j]\") AS AMOUNT";
     
       $result = mysql_query($query);
     if(!$result) die("Query didn't work. " . mysql_error());
   
     $temp = "";         
     while($row = mysql_fetch_array($result))
            {
            $temp = '"'.$row['AMOUNT'].'"';
              }
              $this->GetAmountReturn[$j] .= $temp ;
              }       
         }  
      else
    {
      $this->GetAmountReturn[$j] .=  "\"Full Time Employees\" |";
          
      }
   }
 
 Wishing you a very happy birthday and a year full of things you love
function joinSUPERMARKETNAMEnAMOUNT()
{
//SUPERMARKETNAME select value is from another function
 
 foreach(($this->GetSupermarketNameReturn_value as $i => $SupermarketName)
      {
         $data1 = "{$SupermarketName} | {$this->GetAmountReturn[$i]}  ";
        print_r( $data1);
       }
        }  
}
 
0
 
hernst42Commented:
ok slowly I get the datastructure. The replace with $j is wrong, replace the $j in those two lines with $supermarketID
0
 
firekiller15Author Commented:
is still the same
0
 
hernst42Commented:
hm no clue and without knowing you datastructures it can get very complicated.
0
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