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# Rounding a variable

Posted on 2008-06-13
Medium Priority
236 Views
Last Modified: 2008-06-13
I am using a query to calculate the average of some numbers in a table.

the problem is that when i use this: <? echo \$row->average; ?>

I get numbers with decimals. Is there some way I can round the <? echo \$row->average; ?> to the nearest whole number?

I also need to grab the number of rows used to calculate the average and echo it like <? echo \$row->average; ?> - <? echo \$row->total; ?>

IE: if Mike's Restaurant had 10 records, <? echo \$row->total; ?> would say 10.
``````<?
\$query = "SELECT a.venuename, a.venueid, b.stars, b.reviewtext, AVG( stars ) AS average
FROM venue a, venuereview b
WHERE a.venueid = b.venueid
AND b.switch = '1'
GROUP BY b.venueid
ORDER BY average DESC";

\$result = mysql_query(\$query) or die(mysql_error());

while (\$row = mysql_fetch_object(\$result))
{
?>

<p> <strong><? echo \$row->venuename; ?></strong> - <img src = "<? echo \$row->average; ?>"/></p>

<?php
}
?>
``````
0
Question by:lvollmer
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8 Comments

LVL 82

Expert Comment

ID: 21781151
If you want two decimal places use:
: <? echo round( \$row->average,2); ?>
0

LVL 82

Accepted Solution

hielo earned 2000 total points
ID: 21781161
If you do not want any decimals then use:
<? echo round( \$row->average,0); ?>
0

Author Comment

ID: 21781171
great thats what I need. any idea how I would display the number of records?
0

LVL 82

Expert Comment

ID: 21781209
>>any idea how I would display the number of records?
You should not be asking more than 1 question per post. That's in the user agreement. I'll assume you didn't know that and let it slide this time.

To answer your question, you need to do so right after your query:
...
\$result = mysql_query(\$query) or die(mysql_error());
\$totalRecords = mysql_num_rows( \$result);
...
0

Author Comment

ID: 21781265
i did not know that, sorry.
0

Author Comment

ID: 21781284
I will create a  new question. that solution did not work. keep an eye out for it if you want to help
0

LVL 82

Expert Comment

ID: 21781382
Ahh. I see you are using AVG( stars ) AS average

Try adding count(*) as totalRows to your query so that you get an extra field named totalRows. What I gave you:
\$totalRecords = mysql_num_rows( \$result);

will give you the total number of rows returned for the current query, but that is NOT what you need.
0

Author Comment

ID: 21781392
I actually have a field that just contains teh number 1 as a default, so I am using the SUM function for that - thanks for the help
0

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